N P r = (n!)/((n-r)!)
8 P 4 = (8!)/((8-4)!)
8 P 4 = (8!)/(4!)
8 P 4 = (8*7*6*5*4!)/(4!)
8 P 4 = 8*7*6*5
8 P 4 = 1680
The final answer is 1680
Answer:
y²/324 -x²/36 = 1
Step-by-step explanation:
Where (0, ±b) are the ends of the transverse axis and y = ±(b/a)x describes the asymptotes, the equation of the hyperbola can be written as ...
y²/b² -x²/a² = 1
<h3>Application</h3>
Here, we have transverse axis endpoints of (0, ±18) and asymptotes of y = ±3x, so we can conclude ...
b = 18
b/a = 3 ⇒ a = 18/3 = 6
The equation of the hyperbola in standard form is ...
y²/324 -x²/36 = 1
Answer:
Width of the rectangle = 6.7 ft
length of the rectangle = 10.7 ft
Step-by-step explanation:
ABCD is the rectangle.
AB = length of the rectangle = 4 + x ft
BC = width of the rectangle = x ft
AC = Diagonal of the rectangular field = 12 ft
Since ΔABC is the Right angle triangle. So





By solving above equation we get
x = 6.7 ft
Thus is the width of the rectangle.
And length of the rectangle = 4 + x
⇒ 4 + 6.7
⇒ 10.7 ft
Answer:
Distance covered by the bird before meeting the water is: 51.264 ft
Step-by-step explanation:
Notice that if the bird catches the fish in 2 seconds, then the fish was able to dive down a total of 6 feet before being caught:

So the bird needs to fly in the direction of the hypotenuse of a right angle triangle (see attached image) that has one leg of length (24 ft + 6 ft) = 30 ft, and another one 22.5 ft (half the width of the river.
Such hypotenuse is (using Pythagoras theorem):

Now, in order to find the distance D the bird covers from the top of the tree to the water (marked in red in our image), we use similar triangles. The bigger triangle is that of legs 60 ft and 22.5 ft and hypotenuse 64.08 ft.
The smallest triangle we use in the proportion is the one shaded yellow in the image, which has one leg equal to 24 ft, and unknown hypotenuse:
So we make the proportion between known legs, and hypotenuses:

Answer:
10 gallons 12 seconds.
Step-by-step explanation: The arrow is at 10 and pointing where 12 is.