Answer:
yet I don't have ideal of dis okkk
1) x < 4 the answer is <span> Option C: x E(-infinity,4) (it is strict)
2) </span>2x +6 < 8, and <span>2x < 8 - 6 = 2, and x<2/2=1
the answer is </span>
<span>D. x E (-infinity, 1)
</span>3) <span>X greater than or equal to 8 and x < - 4
</span>X greater than 8 means x ≥ 8
so we have x ≥ 8 and <span> x < - 4
so the answer is </span>
<span>B. x E (-4,8]
</span> 4)
7 > x + 6 or x -2 greater than or equal to 3,
<span>7 > x + 6 or x -2 ≥ 3
</span>
<span>7 -6> x, and 1>x
</span>
x -2 ≥ 3 x<span>≥ 3+2=5
finally
</span>x<1 and x≥5
the answer is
<span>C.x E (1,5]
5)
</span>
|x+3| > 12,
|x+3| = { -(x+3) if <span>x+3<0 or </span><span>(x+3) if </span><span>x+3>0}</span>
so, it is -(x+3)>12 is equivalent to (x+3)< -12 or (x+3)>12
the answer is
<span>B. x + 3 > 12 or x + 3 <-12</span>
First
we have to understand what the domain is. In a nutshell the domain is
the set of all x values that are represented in any given graph. In
this case we do not have a graph but we have the vertex. The x value
is 2, therefore: x
≥ 2.
I
hope this helps, Regards.
Answer:
2
Step-by-step explanation:
4 dvided by 2 is 2
10 didide by 2 is 5
