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4 years ago

At the market, 5 light bulbs cost $9dollar How much do 7 light bulbs cost?

Mathematics

2 answers:

svet-max [94.6K]4 years ago

6 0

9/5= 1.80
1.80x5= 9
so, each light bulb costs 1.80
1.80x7=12.6
the answer is 12.6

Nikitich [7]4 years ago

6 0

Good question!

Quoted answers are NOT Mine! All sources / further information provided:

"The answer is $12.60, because:
$9/ 5 lightbulbs is $1.80 per lightbulb.
Next, you take the $1.80 per light bulb and multiply it by 7 lightbulbs."

Source / further information may be provided at:

brainly.com/question/7418849

I take NO credit for this answer. Credits reserved to @covered0209

I am only here to help, not to get into trouble. I hope you understand

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Suppose we have a binomial experiment with n= 40 trials and a probability of success p= 0.50.Is it appropriate to use a normal a

exis [7]

Answer:

We can approximate to normal.

The parameters of the approximate normal distribution are:

$\mu=np=40*0.5=20\\\\ \sigma=\sqrt{npq} =\sqrt{40*0.5*0.5} =\sqrt{10} =3.16$

$P_B(r>23)\approx 0.314$

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

Step-by-step explanation:

To approximate the binomial distribution to a normal distribution, we can calculate n*p and n*q and if both are bigger than 5 we can do the approximation.

$n*p=n*q=0.5*40=20$

We can approximate to normal.

The parameters of the approximate normal distribution are:

$\mu=np=40*0.5=20\\\\ \sigma=\sqrt{npq} =\sqrt{40*0.5*0.5} =\sqrt{10} =3.16$

The continuity correction factor is used because the binomial is a discrete function and the normal a continous function.

The probability of 23 successes must be expressed in the normal distribution as:

$P_B(r>23)=P_N(r>23+0.5)=P_N(r>23.5)\\\\z=(23.5-20)/3.16=1.1076\\\\P(r>23.5)=P(z>1.1076)=0.134\\\\P_B(r>23)\approx 0.314$

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

3 0

3 years ago

When playing roulette at the Venetian casino in Las Vegas, a gambler is trying to decide whether to bet $5 on the number 27 or t

cricket20 [7]

Answer:

Step-by-step explanation:

Given that:

To bet $5 that the outcome is any one of these five possibilities: 0, 00, 1, 2, 3.

Let Y represent the Amount of net profit

Then, Y= {-5, 30}

The probability distribution of Y is:

Y -5 30

P(Y=y) $\dfrac{33}{38}$ $\dfrac{5}{38}$

a) The expected value of X is given by:

$E[Y] =\sum y P(Y=y)= 30*\dfrac{5}{38}-5*\dfrac{33}{38}$

$=-0.39$

$= -39 \ cents$

On a bet of $5 on the number 25 we are expected to loose 24 cents.

While on a $5 bet that the outcome is any one of the numbers 0,00, or 1 we are expected to loose 39 cents.

Hence, $5 bet on the number 27 is better. Because the expected loss is less in this bet

6 0

3 years ago

At a movie theater, tickets for children cost $6.05 each and adult tickets cost $8.75 each. If ticket sales for a group of 35 pe

insens350 [35]

Answer:

More unknown than equations, the answer cannot be determined

Step-by-step explanation:

We can solve by means of a 2x2 system of equations, we have to:

"x" is the number of children's tickets

"y" is the number of adult tickets

Thus:

blank * x + 8.75 * y = 259

x + y = 35

which means that the number of children in the group cannot be calculated with the supplied data, this is because we have 3 unknowns and there are 2 equations, which means that the system has no solution.

If we assume a value, for example, $ 5

We can solve:

5 * x + 8.75 * y = 259

x + y = 35 => x = 35 - y

replacing we have:

5 * (35 - y) + 8.75 * y = 259

175 - 5 * y + 8.75 * y = 259

- 5 * y + 8.75 * y = 259 - 175

3.75 * y = 84

y = -84 / 3.75

y = 22.4

Thus:

x = 35 - (22.4) = 12.6

there being then 22 adults and 13 children.

6 0

4 years ago

Write your own story problem using mixed numbers that need to be scaled up. The problem should

Neko [114]

Jack has a cake and another half of a cake, Jill has 2 and 2/3rds cakes, Blake has 3 and 2/3rds of a cake, Peter has 4 and 2/3rds of a cake, and Daniel has 2 and a half cakes. How many cakes do they have in total?

1+1/2+2+2/3+3+2/3+4+2/3+2+1/2 = 6/6 (finding the least common multiple of 1, 2, and 3)+3/6+12/6+4/6+18/6+4/6+12/6+3/6= 90/6=15 cakes

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4 years ago

Solve the equation for x 25=1/x

Mkey [24]

Answer:

x = 1/25

Step-by-step explanation:

Solve for x:

25 = 1/x

25 = 1/x is equivalent to 1/x = 25:

1/x = 25

Take the reciprocal of both sides:

Answer: x = 1/25

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3 years ago