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ratelena [41]
2 years ago
11

Pre Calc work, I need help with writing piece wise functions from graphs. Can anyone help? Giving brainliest

Mathematics
1 answer:
Andrei [34K]2 years ago
5 0

The definition of the piece-wise function is:

  • f(x) = 2.5x + 1, -2 \leq x \leq 2
  • f(x) = -3, 2 < x < 6.

<h3>What is a piece-wise function?</h3>

A piece-wise function is a function that has different definitions, depending on the input.

In this problem, for inputs between -2 and 2, the function is a line that goes through (-2,-4) and (2,6). The slope is:

m = (6 - (-4))/(2 - (-2)) = 2.5.

The y-intercept is of b = 1, hence the rule is:

f(x) = 2.5x + 1, -2 \leq x \leq 2

For x greater than 2 and less than 6, the function is constant at -3, hence the rule is:

f(x) = -3, 2 < x < 6.

More can be learned about piece-wise functions at brainly.com/question/27262465

#SPJ1

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Answer:

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Step-by-step explanation:

It was on the unit test review for edge and the answer was that it diverges.

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kvv77 [185]
Hello!

To find the side length you use the equation

a =  \sqrt{2}  \frac{d}{2}

a is side length
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Put in the number we know

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
wel

Answer:

z=\frac{15\sqrt{3}}{2}

Step-by-step explanation:

In leftmost triangle:

opposite side =y

adjacent=a

now, we can use trig formula

tan(60)=\frac{y}{a}

now, we can solve for y

y=atan(60)

In rightmost triangle:

adjacent=b

opposite=y

a+b=15

b=15-a

now, we can use trig formula

tan(30)=\frac{y}{15-a}

now, we can solve for y

y=(15-a)tan(30)

now, we can set them equal

and then we can solve for a

atan(60)=(15-a)tan(30)

\sqrt{3}a\cdot \:3=\frac{\sqrt{3}\left(15-a\right)}{3}\cdot \:3

4\sqrt{3}a=15\sqrt{3}

a=\frac{15}{4}

now, we can find b

b=15-\frac{15}{4}

b=\frac{45}{4}

now, we can use trig formula

cos(30)=\frac{b}{z}

now, we can find z

z=\frac{\frac{45}{4}}{cos(30)}

we can simplify it

and we get

z=\frac{15\sqrt{3}}{2}


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X = -3, y = 2..................
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