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kodGreya [7K]
3 years ago
13

Find the midpoint of points A(-6,9) and B(2,3) graphically.​

Mathematics
1 answer:
daser333 [38]3 years ago
7 0
I’m too lazy to draw a graph but
AB=[2-(-6) , 3-9] = (8,-6)
AB/2 = (8,-6)/2 = (8/2,-6/2) = (4,-3)
mind point of AB is (4,-3) just draw that on a graph and u got it
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Answer:

With 95% confidence when n equals 44, the population mean is between a lower limit of 33.96 and an upper limit of 40.04

Step-by-step explanation:

Confidence Interval = mean + or - Error margin (E)

mean = 37

sd = 10

n = 44

degree of freedom = n - 1 = 44 - 1 = 43

t-value corresponding to 43 degrees of freedom and 95% confidence level is 2.0165

E = t × sd/√n = 2.0165×10/√44 = 3.04

Lower limit = mean - E = 37 - 3.04 = 33.96

Upper limit = mean + E = 37 + 3.04 = 40.04

95% confidence interval is between 33.96 and 40.04

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3 years ago
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Nostrana [21]

Answer:

1/3 × 3y - 1/3 × z

The drawing will help

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3 years ago
How to find the base of a triangle if your height is 6 inches.
AnnyKZ [126]

Answer:

Use this to find your answer.

Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
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kodGreya [7K]

Answer:

C Infinitely Many Solutions

Step-by-step explanation:

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5 0
3 years ago
the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.
suter [353]

Answer:

The width of the photo is 4w^2+6w+4.

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

6w^2+8

The photo is covered by a frame border and the width of the border is

w^2-3w+2

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})

\text{Width of the photo}=6w^2+8-2(w^2-3w+2)

\text{Width of the photo}=6w^2+8-2w^2+6w-4

\text{Width of the photo}=4w^2+6w+4

Therefore the width of the photo is 4w^2+6w+4.

4 0
3 years ago
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