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Artemon [7]
4 years ago
6

Find the equation of a line tangent to the circle (x−1)^2+y^2=26 at the point (2, −5).

Mathematics
1 answer:
77julia77 [94]4 years ago
6 0

Center of circle is ( 1, 0).

Slope of normal passing though ( 1, 0 ) and ( 2, -5 ) is :

m_p=\dfrac{0-(-5)}{1-2}\\\\m_p=-5

So, slope of tangent will be :

m_t=-\dfrac{1}{m_n}\\\\m_t=\dfrac{1}{5}

Equation of tangent :

y-(-5)=\dfrac{1}{5}(x-2)\\\\5y+25=x-2\\\\5y-x+27=0

Hence, this is the required solution.

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Determine if b is a linear combination of a1 a2, and a3. a1 = [ 1 -2 0 ], a2 = [ 0 1 3 ], a3 = [ 6 -6 18 ], b = [ 2 -2 6 ] Choos
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Step-by-step explanation:

First of all we put the vectors in terms of different variables, such as:

a1(1,-2,0)=(a,-2a,0);

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To know that a vector is a linear combination we need to express it like a sum of other different vectors.

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(2,-2,6)=(a+0+6c,-2a+b-6c,0+3b+18c)

We express this sum like a system of equations.

a+6c=2

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3b+18c=6

We solve this system of equations and we can note that the system don't have a solution, so the vector b is not a linear combination of a1, a2, and a3.

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