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Artemon [7]
3 years ago
5

I'll add a photo of the problem! ​

Mathematics
1 answer:
pychu [463]3 years ago
4 0

<u>Answer:</u>

<h2>A. False</h2><h2>B. True</h2><h2>C. False</h2><h2>D. False</h2>

<u>Explanation:</u>

  • A. False

if b = 1 then g ≥ 2

1 + 2 = 3 and 2 < 3

  • B. True

this statement is an opposite situation of the previous statement

if the previous statement is false then this statement is true

  • C. False

the minimum of balls in the bag is 3

2 ≠ 3

  • D. False

if we can determine A, B and C whether they'e true or false then we have enough information

hence this statement is False

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5. Write down the nth term of each of the following G.Ps
yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0
3 years ago
Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle
Whitepunk [10]

Answer:

(6\sqrt{3},\,\frac{5\pi}{6})

Step-by-step explanation:

The radius  r  can be found from the relationship

 r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}

See the attached image.

7 0
3 years ago
Given the information below, is QRS similar to UVT ? If so, give the scale factor.
Leni [432]
I believe it would b A. Hope it helps

8 0
3 years ago
The number of turtles in a pond is four more than twice the number of crocodiles.
cluponka [151]

twice the number is multiplying

 so it would be 2c then add 4 more

 so 2c+4 is the correct equation.

 Answer is B

3 0
2 years ago
Read 2 more answers
You are trying to decide whether to use Uber or Lyft during a vacation. Uber charges $3 to pick up plus an additional $0.25 for
zubka84 [21]

Answer:

6 Miles and the cost is $4.50

Step-by-step explanation:

3+0.25=0.75x

3+0.50x

6=x

0.75x+?

0.75 x 6= 4.50

7 0
3 years ago
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