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Answer:
Explanation:
Note: The table containing the data is attached as a file to this solution.
Also note that the values are given in percentages in the table, the decimal equivalents of those values are used in this calculation.
a)
i) Allele Frequency in the Inuit population
M allele frequency
= 0.835+(0.156/2) = 0.913
N allele frequency
= 0.009 + (0.156/2) = 0.087
ii) Allele frequency in Navojo Indian population
M allele frequency
= 0.845+0.072 = 0.917
N allele frequency
= 0.011+0.072 = 0.083
iii) Allele frequency In Finn population
M allele frequency
= 0.457+0.2155 = 0.6725
N allele frequency
= 0.112+0.2155 = 0.3275
iv)Allele frequency In Russian population
M allele frequency
= 0.399+0.22 = 0.619
N allele frequency
= 0.161+0.22 = 0.381
v) Allele frequency In Aborigines
M allele frequency
= 0.024+0.152 = 0.176
N allele frequency
= 0.672 + 0.152 = 0.824
b)
We can observe that the sum of the frequencies of M and N alleles in each of the populations above is 1. Therefore, all the populations are in Hardy Weinberg's equilibrium.
c)
It can be again observed that the M and N allele frequencies of the Finn and the Russian population are almost the same, then it is safe to say that the Finn and Russian population have had significant intermixing due to migration.
