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2 years ago

if a triangular sail has a vertical height of 83 ft and horizantal length of 40 ft, what is the area of the sail?

Mathematics

1 answer:

Irina18 [472]2 years ago

6 0

Answer:

A = 1660 $ft^{2}$

Step-by-step explanation:

Area of the sail or a triangle is base times height

A = $\frac{1}{2}$ (b x h)

Base is 40 ft (horizontal length)

Height is 83 ft (vertical height)

A = $\frac{1}{2}$ (b x h)

A = $\frac{1}{2}$ (40 x 83) = $\frac{1}{2}$ (3320) = 1660 $ft^{2}$

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Nina [5.8K]

I hope this helps you

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3 years ago

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3 years ago

I need help on this hhhhhhhh

Anon25 [30]

$\huge\text{Hey there!}$

$\mathsf{\dfrac{10^{15}}{10^4}}$

$\mathsf{10^{15}}\\\mathsf{=10\times10\times10\times10\times10\times10\times10\times10\times10\times10\times 10\times10\times10\times10\times10}\\\mathsf{= \boxed{\bf 1,000,000,000,000,000}}$

$\mathsf{\dfrac{\bold{1,000,000,000,000,000}}{10^4}}$

$\mathsf{10^4}\\\mathsf{= 10\times10\times10\times10}\\\mathsf{10\times10=\bf 100}\\\mathsf{100\times100}\\\mathsf{= \boxed{\bf 10,000}}$

$\mathsf{\dfrac{1,000,000,000,000,000}{\bf 10,000}}$

$\mathsf{\dfrac{1,000,000,000,000,000}{10,000}}\\\\\mathsf{= 1,000,000,000,000,000\div 10,000}\\\\\mathsf{= \boxed{\bf 100,000,000,000}}$

$\mathsf{10^{11}}\\\mathsf{10\times10\times10\times10\times10\times10\times10\times10\times10\times10\times10}\\\mathsf{= \boxed{\bf 100,000,000,000}}$

$\mathsf{100,000,000,000= 100,000,000,000= 10^{11}}$

$\boxed{\boxed{\large\text{Answer: BASICALLY }\mathsf{\dfrac{10^1^5}{10^4}\large\text{ is EQUAL to or EQUIVALENT to}}}}\\\boxed{\boxed{\mathsf{10^{11}}\large\text{ because they both give you the result of \bf 100,000,000,000}}}\huge\checkmark$