The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

$\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}$

which would be

$\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}$

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with $2^1=2$ and ending with $2^6=64$ . So in sigma notation, this series is

$\displaystyle\sum_{n=1}^6\frac1{2^n}$

4 0

3 years ago

Mason is preparing for an endurance running competition. On Friday, he ran 15 3/5 miles. On Saturday, he ran twice as much as he

REY [17]

He ran for 34 and 19/20 miles

7 0

3 years ago

Read 2 more answers

48-5+2x3+6.

kkurt [141]

The parentheses must be placed here 48 - (5 + 2) * 3 + 6 in order for the equation to equal 33.

3 0

3 years ago

Let f(x) = x2 - 81. Find f-1(x).

dusya [7]

This is equivalent to finding a function g in which $g(x^2-81)=x$ .

We simply reverse the actions of the initial function by adding 81 back and taking the square root. Therefore, $f^{-1}(x)=\sqrt{x+81}$ .

7 0

3 years ago