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lapo4ka [179]
3 years ago
13

ASAP! Raul needs to make a soil mixture of 2/5 sand, 2/5 clay, and 1/5 peat moss to pot his plants. He has 75 pounds of sand. Ho

w many total pounds of soil will Raul have if he adds clay and peat moss to the sand to make the correct mixture?
A. 112.5 pounds
B. 150 pounds
C. 187.5 pounds
E. 225 pounds
Mathematics
1 answer:
RideAnS [48]3 years ago
7 0

Given:

Raul needs to make a soil mixture of \dfrac{2}{5} sand, \dfrac{2}{5} clay, and \dfrac{1}{5} peat moss to pot his plants.

He has 75 pounds of sand.

To find:

The total pounds of soil.

Solution:

Let x be the total points of soil.

It is given that \dfrac{2}{5} of total soil is sand.

Sand=\dfrac{2}{5}x

He has 75 pounds of sand.

\dfrac{2}{5}x=75

2x=75\times 5

x=\dfrac{375}{2}

x=187.5

The total pounds of soil is 187.5 pounds. Therefore, the correct option is C.

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Scorpion4ik [409]

Answer: IM pretty sure your correct

Step-by-step explanation:

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Ajar contains 4 red marbles numbered 1 to 4 and 10 blue marbles numbered 1 to 10. A marble is
Reptile [31]

Answer:

a)2/7

b)1/2

c)9/14

d)6/7

Step-by-step explanation:

The jar contains 4 red marbles, numbered 1 to 4 which means

Red marbles = (R1) , (R2) , (R3) , (R4)

It also contains 10 blue marbles numbered 1 to 10 which means

Blue marbles = (B1) , (B2) , (B3) , (B4) , (B5) , (B6) , (B7) , (B8) , (B9) , (B10) .

We can calculate total marbles = 4red +10 blues

=14marbled

Therefore, total marbles= 14

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10) =7

Total number of Blue marbles = 10

Blue and even marbles = 5

(a) The marble is red

P(The marble is red)=total number of red marbles/Total number of marbles

=4/14

=2/7

(b) The marble is odd-numbered

Blue marbles with odd number= (B1) , (B3) , (B5) , (B7) , (B9) ,

Red marbles with odd number = (R1) , (R3)

Number of odd numbered =(5+2)=7

P(marble is odd-numbered )= Number of odd numbered/ Total number of marbles

P(marble is odd-numbered )=7/14

=1/2

(C) The marble is red or odd-numbered?

Total number of red marbles = 14

Number of red and odd marbles = 2

The marbles that has odd number = (R1) , (R3) ,(B1) , (B3) , (B5) , (B7) , (B9) =7

n(red or even )= n(red) + n(odd)- n(red and odd)

=4+7-2

=9

P(red or odd numbered)= (number of red or odd)/(total number of the marble)

= 9/14

(d) The marble is blue or even-numbered?

Number of Blue and even marbles = 5

Total number of Blue marbles = 10

Number of blue that are even= 5

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10)

=7

n(Blue or even )= n(Blue) + n(even)- n(Blue and even)

= 10+7-5 =12

Now , the probability the marble is blue or even numbered can be calculated as

P(blue or even numbered)= (number of Blue or even)/(total number of the marble)

= 12/14

= 6/7

6 0
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schepotkina [342]

Answer:

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Step-by-step explanation:

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allsm [11]

Answer:

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Step-by-step explanation:

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the second is 1/5 of galloon

the third is 1/2 of gallon adding them together

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