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2 years ago

What are three differentnumbers that could by multipliedby a power of ten to equal 7,500?

Mathematics

1 answer:

stich3 [128]2 years ago

3 0

5,10,and 100 hope this helped

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Use inverse operations to solve the following:<br> 4.9 + z = -9

ale4655 [162]

The answer is z = -13.9

In order to solve this, you need to use inverse operations. The inverse operation of addition is subtraction. So, this is the function we'll use

4.9 + z = -9 ----> subtract 4.9 from both sides

z = -13.9

5 0

2 years ago

you got a new credit card with an interest rate of 18% compounded monthly and no minimum payment. you go on a shopping spree and

just olya [345]

The total amount owed after 6 months will be found using the formula:
FV=P(1+r/100*n)^n
P=principle=$10000
r=rate=18%
n=terms=0.5

FV=10000(1+18/2*100)^0.5
FV=$10,440.30651
Thus the amount owed will be $10440.30651

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2 years ago

Help timed help plss!!

PSYCHO15rus [73]

Answer:

V1 = Base x Height = 43 x 15 = 645 (mm3)

V2 = Base x Height = 12 x 7 = 84 (mm3)

Hope this helps!

3 0

2 years ago

Read 2 more answers

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers

Need help asap pls pls pls

Sliva [168]

Answer:

bqidhiwodxh

Step-by-step explanation:

627e29302990331 e7894094902

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6 0

1 year ago

What are three differentnumbers that could by multipliedby a power of ten to equal 7,500?​

What are three differentnumbers that could by multipliedby a power of ten to equal 7,500?