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aksik [14]
3 years ago
13

A rectangle has length 127.3 cm and width 86.5 cm, both correct to 1 decimal place. Calculate the upperbound and the lowerbound

for the perimeter of the rectangle. pls answer fast. i need all the workings.
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
8 0

Answer:

Correct to 1dp

127.3 cm = 127.0 cm

86.5 cm = 87.0 cm

Upper limits:

127.0 cm = 127.05 cm

87.0 cm = 87.05 cm

Lower Limits:

127.0 cm = 126.95 cm

87.0 cm = 86.95 cm

upper limit of perimeter of rectangle:

P = 2(l+w)

= 2(127.05 + 87.05)

= 2(214.1)

= 428.2 cm

lower limit of perimeter of rectangle:

P = 2(l+w)

= 2(126.95 + 86.95)

= 2(213.9)

= 427.8 cm

therefore;

427.8 cm \leqslant perimeter < 428.2cm

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Plese help with this qashtion ?
tatiyna
A + (b + c) * d
a=15
b=25
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