![\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh\qquad \begin{cases} B=\textit{area of the base}\\ h=height \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20pyramid%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B1%7D%7B3%7DBh%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AB%3D%5Ctextit%7Barea%20of%20the%20base%7D%5C%5C%0Ah%3Dheight%0A%5Cend%7Bcases%7D)
now, the first one, on the far-left.... can't see the height.. but I gather you do, now as far as its Base area, well, the bottom is just a 12x12 square, so the area of its base is just 12*12
now, the middle pyramid, has a height of 6, the base is also a square, 8x8, so the Base area is just 8*8
now the last one on the far-right
has a height of 8, the Base is a Hexagon, with sides of 6
Answer:
2
Step-by-step explanation:
BECAUSE N IS ONE TERM AND P IS THE OTHER ONE sorry for all caps i just relized.
1 meter = 100cm
so, divide 10.5 by 100
therefore you will move the decimal place 2 places to the right
(because of the two zeros)
and you will get 0.105 meters
y = -
x - 1
the equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange - 7x + 5y = 12 into this form
add 7x to both sides
5y = 7x + 12 ( divide all terms by 5 )
y =
x +
← in slope- intercept form
with slope m = ![\frac{7}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B5%7D)
given a line with slope m then the slope of a line perpendicular to it is
perpendicular slope = -
= - ![\frac{5}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B7%7D)
The partial equation of the perpendicular line is
y = -
x + c
to find c substitute (- 7, 4 ) into the partial equation
4 = 5 + c ⇒ c = 4 - 5 = - 1
y = -
x - 1 ← in slope- intercept form