What is the value of e? A 32 B 238 C 58 D 122
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Let "c" and "q" represent the numbers of bottles of Classic and Quantum that should be produced each day to maximize profit. The problem conditions give rise to 3 inequalities:
.. 0.500c +0.550q ≤ 100 . . . . . . . liters of water
.. 0.600c +0.200q ≤ 100 . . . . . . . kg of sugar
.. 0.1c +0.2q ≤ 32 . . . . . . . . . . . . . grams of caramel
These can be plotted on a graph to find the feasible region where c and q satisfy all constraints. You find that the caramel constraint does not come into play. The graph below has c plotted on the horizontal axis and q plotted on the vertical axis.
Optimum production occurs near c = 152.17 and q = 43.48. Examination of profit figures for solutions near those values reveals the best result for (c, q) = (153, 41). Those levels of production give a profit of 6899p per day.
To maximize profit, Cartesian Cola should produce each day
.. 153 bottles of Classic
.. 41 bottles of Quantum per day.
Profit will be 6899p per day.
_____
The problem statement gives no clue as to the currency equivalent of 100p.
.. 0.500c +0.550q ≤ 100 . . . . . . . liters of water
.. 0.600c +0.200q ≤ 100 . . . . . . . kg of sugar
.. 0.1c +0.2q ≤ 32 . . . . . . . . . . . . . grams of caramel
These can be plotted on a graph to find the feasible region where c and q satisfy all constraints. You find that the caramel constraint does not come into play. The graph below has c plotted on the horizontal axis and q plotted on the vertical axis.
Optimum production occurs near c = 152.17 and q = 43.48. Examination of profit figures for solutions near those values reveals the best result for (c, q) = (153, 41). Those levels of production give a profit of 6899p per day.
To maximize profit, Cartesian Cola should produce each day
.. 153 bottles of Classic
.. 41 bottles of Quantum per day.
Profit will be 6899p per day.
_____
The problem statement gives no clue as to the currency equivalent of 100p.
QUESTION 12
The given figure has five unequal sides.
The perimeter is the distance around the figure.
So we add all the lengths of the sides of the rectangle to get,
We regroup the like terms to obtain,
This will simplify to give us,
QUESTION 13
The given figure has two pairs of sides that are equal in length and three unequal sides.
The perimeter can be found by adding all the lengths of the sides of the of the figure.
This will give us
We regroup like terms to obtain,
This finally simplifies to ,
.
QUESTION 14
This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.
We add all the lengths of the sides of the plane figure to get,
This will simplify to give us,
The given figure has five unequal sides.
The perimeter is the distance around the figure.
So we add all the lengths of the sides of the rectangle to get,
We regroup the like terms to obtain,
This will simplify to give us,
QUESTION 13
The given figure has two pairs of sides that are equal in length and three unequal sides.
The perimeter can be found by adding all the lengths of the sides of the of the figure.
This will give us
We regroup like terms to obtain,
This finally simplifies to ,
.
QUESTION 14
This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.
We add all the lengths of the sides of the plane figure to get,
This will simplify to give us,