Answer: neither

Explanation:

x^3 can be either even or odd
Ex: x = 2 then 2^3 = 8 = even
Ex: x = 3 then 3^3 = 27 = odd

x^2 can also be either even or odd
Ex: x = 2 then 2^2 = 4 = even
Ex: x = 3 then 3^3 = 9 = odd

Since both can be even and odd

Even/Odd + Even/Odd = Even/Odd

So the result will be either even or odd

5 0

3 years ago

Plsss help me with this:(((

garri49 [273]

Answer:

$\frac{2 {a}^{2} }{3 {b}^{3} } \div \frac{6 {a}^{3} }{5 {b}^{2} } = \frac{2 {a}^{2} }{3 {b}^{3} } \times \frac{5 {b}^{2} }{6 {a}^{3} } = \frac{5}{9ab} \\ \\ \frac{ {x}^{2} - 5x + 6}{ {x}^{2} - 6x + 9} + \frac{4x - 12}{{x}^{2} - 6x + 9} \\ = \frac{{x}^{2} - 5x + 6 + 4x - 12}{{x}^{2} - 6x + 9} \\ = \frac{{x}^{2} - x - 6}{{x}^{2} - 6x + 9} \\ = \frac{(x - 3)(x + 2)}{(x - 3)(x - 3)} \\ = \frac{(x + 2)}{(x - 3)} \\ \\ \frac{3a}{a - b} - \frac{a + 2b}{a - b} \\ = \frac{3a - a + 2b}{a - b} \\ = \frac{2a - 2b}{a - b} \\ = 2\frac{a - b}{a - b} \\ = 2$

7 0

3 years ago