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Makovka662 [10]

3 years ago

12

Plz help as quick as possible!

2 answers:

Zigmanuir [339]3 years ago

7 0

65% maybe wrong tell me if I am

kompoz [17]3 years ago

6 0

average =65%

average = (60+70)/(100+100)*100

= 130/200*100

= 65%

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The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

a

$y(t) = y_o e^{\beta t}$

b

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

c

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

So

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

So

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

So

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

So

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

so

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

3 times the sum of 1/3 of a number and 8 is 11

photoshop1234 [79]

Algebraically, that would be expressed as:

$3(\frac{1}{3}n +8) = 11$

7 0

3 years ago

A polynomial has two terms.

alexira [117]

Not sure if that is the entire question, but yes, it does. Poly comes from the Greek polus or polloi meaning much or many.

3 0

3 years ago

A bag contains 50 lottery balls, numbered 1-50. A ball is chosen at random, then a month of the year is selected. What is the pr

Morgarella [4.7K]

Answer:

4/75

Step-by-step explanation:

We have two sample spaces

1.Lottery balls

2. Month of the year

For lottery balls the sample space is S= 50

Multiples of 3 between 1 and 50 are

(3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48)= 16 in numbers

Hence the probability of choosing a multiple of 3

Pr(multiple of 3) = 16/50= 8/25

Also the sample space for months of the year is S= 12

Two months starts with letter m, March and may

Pr(of months with m) = 2/12= 1/6

the probability of choosing a multiple of 3 and a month starting with the letter M= 8/25*1/6= 8/150= 4/75

6 0

4 years ago

I really don't get this im so confused

Tanzania [10]

Answer:

Step-by-step explanation:

m<ABC=90 because of Angle inscribed in Semicircle Theorem

6 0

3 years ago

Read 2 more answers