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3 years ago

6

Select the correct answer. Select the graph of the equation below. A. B. C. D.

1 answer:

Fudgin [204]3 years ago

5 0

The equation is in slope-intercept form. Slope-intercept form is y = mx + b. B stands for the y-intercept. Looking at these graphs, the only graph that has a y-intercept of 1 is A. The order of the images may have gotten messed up, but look for the one where there’s a line through the vertical axis (Y) at 1.

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B is the midpoint of AC. AB = 2x+12 and BC = 5x + 10. Find AC

3241004551 [841]

Answer:

x=6

Step-by-step explanation:

/AB/=2x+12

/BC/=5x+10

3x+2=5x-10 subtract 2 from both sides

3x=5x-12 subtract 5x from both sides

-2x=-12 divide both sides by -2x

x =6

5 0

2 years ago

HELP AND THEY ARE all Diffrent questions

Anarel [89]

Answer:1)720 white stripes and 840 red stripes

2)48 divided by 4=12 feett per second

3)265 divded by 4 than divide 425 by what you got before

4)3 times 10=30

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A square of the side lenght of 6cm has the same area as this rectangle . find the perimeter of the rectangle.

Aleksandr-060686 [28]

Answer:

The perimeter of the rectangle is 26 cm

Step-by-step explanation:

First find the area of the square by multiplying 6 by itself

A = 6 cm * 6 cm = 36 sq cm

Since the rectangle has the same area as the square, we can say that w * 9 = 36 sq cm

w * 9 = 36

Divide both sides by 9 to isolate the variable, w

w * 9 / 9 = 36 / 9

w = 4 cm

The width of the rectangle is 4 cm so now we just use that to find the perimeter of the rectangle

P = 2(9) + 2(4) = 26 cm

3 0

2 years ago

The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section

lisabon 2012 [21]

Answer:

$\therefore y_2(x)=-\frac{e^{-6x}}{8}$

The general solution is

$y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}$

Step-by-step explanation:

Given differential equation is

y''-4y'+4y=0

and $y_1(x)=e^{2x}$

To find the $y_2(x)$ we are applying the following formula,

$y_2(x)=y_1(x)\int \frac{e^{-\int P(x) dx}}{y_1^2(x)} \ dx$

The general form of equation is

y''+P(x)y'+Q(x)y=0

Comparing the general form of the differential equation to the given differential equation,

So, P(x)= - 4

$\therefore y_2(x)=e^{2x}\int \frac{e^{-\int 4dx}}{(e^{2x})^2}dx$

$=e^{2x}\int \frac{e^{-4x}}{e^{4x}}dx$

$=e^{2x}\int e^{-4x-4x} \ dx$

$=e^{2x}\int e^{-8x} \ dx$

$=e^{2x}. \frac{e^{-8x}}{-8}$

$=-\frac{e^{-6x}}{8}$

$\therefore y_2(x)=-\frac{e^{-6x}}{8}$

The general solution is

$y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}$

4 0

3 years ago

Give me the answer fast now now please thank

Zolol [24]

Answer:

#4

Step-by-step explanation:

EDI/HDE

hope it helps

8 0

3 years ago

Read 2 more answers