Probability=number of specific outcomes / total possible outcomes
P(g)=12/(12+8)
P(g)=12/20
P(g)=3/5
Answer:
x = 2
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
(4+(4•(x-2)))-(2•(x+1)-x) = 0
Step 2 :
Equation at the end of step 2 :
(4 + 4 • (x - 2)) - (x + 2) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
3x - 6 = 3 • (x - 2)
Equation at the end of step 4 :
3 • (x - 2) = 0
Step 5 :
Equations which are never true :
5.1 Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.2 Solve : x-2 = 0
Add 2 to both sides of the equation :
x = 2
One solution was found :
x = 2
Processing ends successfully
plz mark me as brainliest :)
Well I don't know where inequalities would come in but the third length would be solved as follows.
a^2+b^2=c^2
10^2+18^2=424
Answer;
I hope this is correct, its what I would do if I had this equation.
Answer:
$0.18
Step-by-step explanation:
we need to set up two simultaneous equations
using variables, pencils = p and erasers = e
3 pencils and 2 erasers, the cost is $0.76
3p + 2e = $0.76
2 pencils and 4 erasers, the cost is $1.04.
2p + 4e = $1.04
we now have
3p + 2e = $0.76
2p + 4e = $1.04
to make the number of erasers the same, multiply the first equation by 2 to give 4e
2(3p + 2e = $0.76)
6p + 4e = $1.52
now we have the same number of erasers for both equations
6p + 4e = $1.52
2p + 4e = $1.04
subtract across: 6p - 2p = 4p, 4e - 4e = 0, $1.52 - $1.04 = $0.48
we are left with 4p = $0.48
divide both sides by 4
p = $0.12
1 pencil = $0.12
go back to the start of both equations and use one of them to find 1 eraser. I'll use 3p + 2e = $0.76
input $0.12 in p
3($0.12) + 2e = $0.76
$0.36 + 2e = $0.76
subtract $0.36 on both sides
2e = $0.76 - $0.36
2e = $0.40
divide 2 on both sides
e = $0.20
1 eraser = $0.20
How much more does 1 eraser cost than 1 pencil?
we now know 1 pencil = $0.12 and 1 eraser = $0.20
find the difference between them
$0.20 - $0.12 = $0.18
final answer= $0.18
