Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer:
150 square inches.
Step-by-step explanation:
Since the surface area of a cube is 6 times the square of the side length of the cube, then that means the surface area of a cube that has a side length of 5 has a surface area of 6 x 5 x 5. 5 times 5 = 25, and 25 x 6 = 150
<u>Answer:</u> 100
<u>Reasoning:</u> The median is the "middle value" and to find it put the numbers in order from least to greatest.
22, 43, 100, 102, 108.
now take a number from both sides
43, 100, 102
Once again.
100
So 100 is the median.
Answer:
t=5/10n
Step-by-step explanation:
The question wants to know how much time it takes to run one lap, not how many laps can be run in a certain amount of time.
Blue: = because the equal sign is stating that it’s the same.
