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topjm [15]
3 years ago
15

Sarah's age is ten years more than twice Tanya's age. The sum of their ages is 64. How old is Sarah? ​

Mathematics
1 answer:
givi [52]3 years ago
6 0

Sarah is 46.

n = Tonya’s age

2n + 10 = Sarah’s age

2n + 10 + n = 64

3n + 10 = 64

3n - 10 = 64 - 10

3n = 54

3n/3 = 54/3

n = 18

18 x 2 = 36

36 + 10 = 46

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Lola rolls two fair number cubes. What is the probability that the two numbers Lola rolls include at least one 4 and have a prod
Oxana [17]
Lola rolls two fair number cubes what is the probability that the two numbers Lola rolls include at least one 4 and have product of at least 16? Probably half of a chance
3 0
3 years ago
Thank you!!!!!!!!!!!!!!!
OverLord2011 [107]

Answer:

Binomial distribution requires all of the following to be satisfied:

1. size of experiment (N=27) is known.

2. each trial of experiment is Bernoulli trial (i.e. either fail or pass)

3. probability (p=0.14) remains constant through trials.

4. trials are independent, and random.

Binomial distribution can be used as a close approximation, with the  usual assumption that a sample of 27 in thousands of stock is representative of the population., and is given by the probability of x successes (defective).

P(x)=C(N,x)*p^x*(1-p)^(n-x)

where N=27, p=0.14, and C(N,x) is the number of combinations of x items out of N.

So we need the probability of <em>at most one defective</em>, which is

P(0)+P(1)

= C(27,0)*0.14^0*(0.86)^(27) + C(27,1)*0.14^1*(0.86^26)

=1*1*0.0170 + 27*0.14*0.0198

=0.0170+0.0749

=0.0919


4 0
3 years ago
Molly recives 20 mins of homework every night.Her brother says that he gets 10 times as much homework than her and he is in high
mina [271]
I would believe him. it comes down to about 3 hours and some change. i’m in high school and its a reasonable amount.
8 0
3 years ago
HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid
Harlamova29_29 [7]

Answer:  Missing parts are,

In first blank,  AD\cong DC,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

\angle BDA\cong \angle BDC ( right angles )

BD\cong BD ( reflexive)

Thus, By SAS ( side angle side )postulate,

\triangle ADB\cong \triangle CDB

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

AB\cong CB

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.




7 0
3 years ago
Read 2 more answers
Question 2 (5 points)
Anuta_ua [19.1K]

Answer:

The greatest common factor is 8xyz

Step-by-step explanation:

To find the greatest common factor of an expression involving numbers and variables, we find each greatest common factor separately.

Numbers:

48, 24 and 56.

We find the greatest common factor factoring them simultaneously while all can be factored by the same number. The GCF is the multiplication of the factors. So

48 - 24 - 56|2

24 - 12 - 28|2

12 - 6 - 14|2

6 - 3 - 7|

They cant be factored by the same factors anymore, so the numeric GCF is 8.

Variables:

For each variable, the GCF will be the lowest exponent.

Variable x: We have exponents 1, 2 and 2. So the GCF is x^1 = x

Variable y: We have exponents 3, 3 and 1. So the GCF is y^1 = y

Variable z: We have exponents 1, 1 and 1. So the GCF is z^1 = z

The greatest common factor is:

8*x*y*z = 8xyz

4 0
3 years ago
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