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Elden [556K]
3 years ago
15

Write the equation of the graph shown below in factored form.

Mathematics
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

(x+2)2(x+1)(x+4)

Because

x=-4. x=2. x=-1

(x+4). (x+2). (x+1)

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(5/6)^4x=(36/25)^9-x, please help solve for x, and the 9-x is all superscript
stiks02 [169]
\frac{36}{25}=\frac{6^2}{5^2}=\left(\frac{6}{5}\right)^2=\left(\frac{5}{6}\right)^{-2}\\\\therefore:\\\\\left(\frac{5}{6}\right)^{4x}=\left[\left(\frac{5}{6}\right)^{-2}\right]^{9-x}\\\\\left(\frac{5}{6}\right)^{4x}=\left(\frac{5}{6}\right)^{-2(9-x)}\iff4x=-2(9-x)\\\\4x=-2\cdot9-2\cdot(-x)\\\\4x=-18+2x\ \ \ \ \ |subtract\ 2x\ from\ both\ sides\\\\2x=-18\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=-9}


Use:\\a^{-n}=\left(\frac{1}{a}\right)^n\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\\left(\frac{a}{b} \right)^n=\frac{a^n}{b^n}
6 0
2 years ago
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kherson [118]

Answer:

Step-by-step explanation:

y = -4x + 6.....switch x and y and solve for y

x = -4y + 6 ....subtract 6 from both sides

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What is the length of the diameter of a circle inscribed in a right triangle with the length of hypotenuse c and the sum of the
jeyben [28]

Answer:

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Step-by-step explanation:

In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).

The sum of the lengths of the tangents from points A and B on side "c" is ...

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Now, the problem statement defines the sum of side lengths as ...

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and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...

  m -d = c

  m - c = d . . . . add d-c

The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.

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3 years ago
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nata0808 [166]

Answer:

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Step-by-step explanation:

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Express the ratio in simplest form 85 out of 102
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1.2 is the answer to your question.
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