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olga_2 [115]
3 years ago
15

A rock is released from rest and freely falls 70 m to the ground. What is its velocity just before impact? A. 1.2 m/s B. 7.0 m/s

C. 9.8 m/s D. 12 m/s​
Mathematics
1 answer:
Yuri [45]3 years ago
5 0

Answer:

37.04 m/s

Step-by-step explanation:

we can use the equation x = x0 + v0t + 1/2at^2

a = -9.8 m/s^2, the acceleration due to gravity

x0 = 70 m, the starting point of x

v0 = 0 m/s

x = 0

this will allow us to solve for time

0 = 70 + 0 +-4.9t^2

t = 3.779

now we can use the equation v = v0 + at

v = 0 + 9.8(3.77)

v = 37.04 m/s

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-f(x) = 2x + 6 Find f(-4)
jenyasd209 [6]
The answer is 1 Bcuz u have to first plug in -4 for f then solve the equation by adding like terms and dividing
4 0
3 years ago
Rewrite the following equation in slope-intercept form<br> y-6=-9(x-5)
gogolik [260]

Answer:

y=-9x+51

Step-by-step explanation:

-9x+45=y-6

add 6 to both sides to get

-9x +51=y

7 0
3 years ago
9. If f(x) = 5x-4 and f(2a) =156 , then what is the value of a?
solmaris [256]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f(x) = 5x - 4

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f(2a) = 5(2a) - 4

f(2a) = 10a - 4

156 = 10a - 4

10a - 4 = 156

Add sides 4

10a - 4 + 4 = 156 + 4

10a = 160

Divide sides by 10

\frac{10a}{10}  =  \frac{160}{10}  \\

a = 16

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7 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD=√2 cm.
Zielflug [23.3K]

Given that triangle ABC is right angle triangle. CD is altitude such that AD=BC

ABC is a right angle triangle so apply Pythogorean theorem

AC^{2} + BC^{2} = AB^{2}

AC^{2} + AD^{2} = AB^{2}      (Given that AD = BC)

AC^{2} + AD^{2} = 3^{2}      (Given that AB=3)

AC^{2} + AD^{2} = 9 ...(i)

ADC is a right angle triangle so apply Pythogorean theorem

AD^{2} + CD^{2} = AC^{2}

AD^{2}+(\sqrt{2})^2= AC^{2}

AD^{2}+2= AC^{2}

AD^{2}=AC^{2} -2 ...(ii)


Plug value (ii) into (i)

AC^{2} + AC^{2}-2 = 9

2AC^{2} -2=9

2AC^{2} =11

AC^{2} =\frac{11}{2}

AC=\sqrt{\frac{11}{2} }


Hence final answer is AC=\sqrt{\frac{11}{2} }

8 0
3 years ago
Read 2 more answers
Determine the perimeter of a triangle with sides that measure 16.2 inches, 10.04 inches and 12.2 inches.
Ksju [112]

Answer:

Step-by-step explanation:

Solution,

The perimeter of a triangle=Sum of all sides

16.2in+10.04in+12.2in\\=38.44inches

Hope it will help you a lot.

5 0
2 years ago
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