Sin C = AB / AC
We have AC. We need to calculate AB
ABC is a right triangle. Therefore, AC² = AB²+BC²
82² = AB ² + 80² => AB² = 82² - 80²
AB = 18
Sin C = 18/82 = 9/41
Good luck
Answer:
2.66666666667
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Use the law of cosines:</u>
- cos C = (25² + 27² - 28²)/(2*25*27)
- cos C = 0.4222
- m∠C = arccos 0.4222
- m∠C = 65°
There are two triangles that are 15cm in height and 10cm in width so you do 15 times 10 which is 150 then divided it by 2 because it a triangle to get 75 then because there is 2 you then multiply it by 2 again and you get 150
Answer:
i dont now
Step-by-step explanation:
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