In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number.
If a function is defined as

where both
are continuous functions, then
is also continuous where defined, i.e. where 
So, in your case, this function is continous everywhere, except where

To solve this equation, we can use the formula 
It means that, if the leading terms is 1, then the x coefficient is the opposite of the sum of the roots, and the constant term is the product of the roots.
So, we're looking for two terms whose sum is 7, and whose product is 12. These numbers are easily found to be 3 and 4.
So, this function is continuous for every real number different than 3 or 4.
Answer:
p = 8000 + 2(6000)
20000
Step-by-step explanation:
Given that:
Profit in 1988 = 6000
Profit in 2003 = 8000 more Than double the profit made in 1998
Hence profit in 2003 (p) can be expressed as :
p = 8000 + 2(6000)
Hence profit in 2003
p = 8000 + 12000
p = 20,000
The answer is option c (-1,0)
Solving the equation you get that the zeros of this are approximately
x ≈ -2.8019
x ≈ -1.4450
x ≈ 0.24698
Then the function has three real roots, but none of them is within the range (-1,0)
Below is a graph of the function.