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2 years ago

What percentage of a dollar is the value of 4 dimes?

Mathematics

2 answers:

sammy [17]2 years ago

8 0

Answer:

a. 40%

b. 8%

c. 135%

Step-by-step explanation:

I-I hope dis helped n if it’s wrong IM TRUELY SORRY

timofeeve [1]2 years ago

3 0

Answer:

40%

Step-by-step explanation:

recall that a dime is 10 cents (or $0.10)

hence 4 dimes = 40 cents = $0.40

percentage of 4 dimes out of a dollar

= ($0.40 / $1.00) x 100%

= 40%

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Answer:

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Step-by-step explanation:

Using the SOH CAH TOA identity

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Step-by-step explanation:

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What are the solutions to the quadratic equation (5y + 6)2 = 24? y = StartFraction negative 6 + 2 StartRoot 6 EndRoot Over 5 End

Paladinen [302]

Answer:

there are two solutions:

a) $y=\frac{-6+2\sqrt{6} }{5}$ , and

b) $y=\frac{-6-2\sqrt{6} }{5}$

Step-by-step explanation:

In the equation: $(5y+6)^2=24$ , since a perfect square with the unknown "y" is isolated on the left of the equal sign, we start by applying the square root on both sides of the equality, and then on isolating the unknown:

$(5y+6)^2=24\\\sqrt{(5y+6)^2} =+/-\sqrt{24} \\(5y+6)=+/-\sqrt{6*4} \\(5y+6)=+/-2\sqrt{6}\\5y=-6+/-2\sqrt{6}\\y=\frac{-6+/-2\sqrt{6} }{5}$

Therefore there are two solutions:

a) $y=\frac{-6+2\sqrt{6} }{5}$ , and

b) $y=\frac{-6-2\sqrt{6} }{5}$

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A student's course grade is based on one midterm that counts as % of his final grade, one class project that counts as % of

Andrei [34K]

Answer:

The overall score is 75.6

Letter grade is C

Step-by-step explanation:

The question has missing details (See comment section for complete question).

From the complete question, we have:

Proportion:

$Midterm = 15\%$

$Project = 25\%$

$Assignment = 40\%$

$Exam = 20\%$

Scores

$Midterm = 66$

$Project = 90$

$Assignment = 75$

$Exam = 66$

Solving (a): The overall score

To do this, we simply calculate the mean of the given data.

The mean is calculated by multiplying each proportion by the scores..

So, we have:

$Overall = 15\% * 66 + 25\% * 90 + 40\% * 75 + 20\% * 66$

$Overall = 9.9 + 22.5 + 30 + 13.2$

$Overall = 75.6$

Solving (b): The letter grade

From the question, we have:

$A: Mean \ge 90$

$B: 80 \le Mean < 90$

$C: 70 \le Mean < 80$

The overall score falls in the following category:

$C: 70 \le Mean < 80$

Because:

$70 \le 75.6 < 80$

Hence, the letter grade is C

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2 years ago