What is the solution to the equation below? Round your answer to two
1 answer:
Answer:
D. x=5
The answer is x=4.50 then it is rounded off to 5. So, the answer is 5.
Step-by-step explanation:
Find the domain of the inequality:
Rearrange terms to the left side of the equation:
Divide both sides of the inequality by the coefficient of the variable:
=>
The domain of the inequality is:
Convert logarithm to exponential form:
Calculate the power:
Rearrange terms to the left side of the equation:
Calculate:
Divide both sides of the equation by the coefficient of the variable:
=>
=>
Round the number:
Answer:
=>
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Answer:
Unfortunately, your answer is not right.
Step-by-step explanation:
The functions whose graphs do not have asymptotes are the power and the root.
The power function has no asymptote, its domain and rank are all the real.
To verify that the power function does not have an asymptote, let us make the following analysis:
The function , when x approaches infinity, where does y tend? Of course it tends to infinity as well, therefore it has no horizontal asymptotes (and neither vertical nor oblique)
With respect to the function we can verify that if it has asymptote horizontal in y = 0. Since when x approaches infinity the function is closer to the value 0.
For example: 1/2 = 0.5; 1/1000 = 0.001; 1/100000 = 0.00001 and so on. As "x" grows "y" approaches zero
Also, when x approaches 0, the function approaches infinity, in other words, when x tends to 0 y tends to infinity. For example: 1 / 0.5 = 2; 1 / 0.1 = 10; 1 / 0.01 = 100 and so on. This means that the function also has an asymptote at x = 0
Answer:
The constant of variation is $1.50
Step-by-step explanation:
Given
Point 1 (1,2)
Point 2 (5,8)
Required
Constant of Variation
Though the graph would have assisted in answering the question; its unavailability doesn't mean the question cannot be solved.
Having said that,
the constant variation can be solved by calculating the gradient of the graph;
The gradient is often represented by m and is calculated as thus
Where
By substituting values for x1,x2,y1 and y2; the gradient becomes
Hence, the constant of variation is $1.50