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tatyana61 [14]
2 years ago
6

What is the solution to the equation below? Round your answer to two

Mathematics
1 answer:
noname [10]2 years ago
5 0

Answer:

D. x=5

The answer is x=4.50 then it is rounded off to 5. So, the answer is 5.

Step-by-step explanation:

Find the domain of the inequality:2x-1\geq 0

Rearrange terms to the left side of the equation:2x\geq 1

Divide both sides of the inequality by the coefficient of the variable:

=> x\geq \frac{1}{2}

The domain of the inequality is:x\geq \frac{1}{2}

Convert logarithm to exponential form:2^{3}=2x-1

Calculate the power:8=2x-1

Rearrange terms to the left side of the equation:-2x= -8-1

Calculate:-2x=-9

Divide both sides of the equation by the coefficient of the variable:x=\frac{-9}{-2}

=> x=\frac{9}{2}

=>x=4.5\\

Round the number: x=4.50

Answer: x=4.50

=> x=5

Read to know more about log equation:

brainly.com/question/16692243?referrer=searchResults

#SPJ10

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At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

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\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

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• Yogi is planning a concert for his animal friends. He arranges his chairs and if he makes 8 rows he was
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3 years ago
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