2x^2 – 7x - 4 = 0(quadratic equation)
2 answers:
Answer:
See below for answers and explanations (along with a graph)
Step-by-step explanation:
<u>X-intercepts:</u>
2x²-7x-4=0
(2x+1)(x-4)=0
2x+1=0 and x-4=0
x=-1/2 and x=4
<u>Axis of Symmetry:</u>
x=-b/2a
x=-(-7)/2(2)
x=7/4
<u>Vertex:</u>
f(x)=2x²-7x-4
f(7/4)=2(7/4)² - 7(7/4) - 4
f(7/4)=2(49/16) - 49/4 - 4
f(7/4)=98/16 - 196/16 - 64/16
f(7/4)=-162/16
(h,k) = (7/4,-81/8)
Refer to graph to see these visually
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