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MArishka [77]
2 years ago
8

Help plz answer quick

Mathematics
1 answer:
Inessa [10]2 years ago
8 0

Answer:

around 1.67 inches

Step-by-step explanation:

We have to divide 1.25 inches by 0.75 inches to get the scale factor.

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Pretest: Unit 5 Question 12 of 21 Use the substitution method to solve the system of equations. Choose the correct ordered pair.
Gala2k [10]

Answer:

(10, - 9 )

Step-by-step explanation:

Given the 2 equations

y = - 2x + 11 → (1)

y = - 3x + 21 → (2)

Substitute y = - 2x + 11 into (2)

- 2x + 11 = - 3x + 21 ( add 3x to both sides )

x + 11 = 21 ( subtract 11 from both sides )

x = 10

Substitute x = 10 into either of the 2 equations and evaluate fir y

Substituting into (1)

y = - 2(10) + 11 = - 20 + 11 = - 9

solution is (10, - 9 )

3 0
3 years ago
Find the rate of change of the function h(x) = 2 x on the interval 2 ≤ x ≤ 4. The rate of change is a0.'
IceJOKER [234]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
3 years ago
Number product of a number ​
yuradex [85]

Answer:

The answer to a multipaction problem

Step-by-step explanation:

The values you are multiplying are called the factors. The answer in a multiplication problem is called the product. You find the product when you multiply two or any number of factors.

8 0
2 years ago
Three point zero one divided by seven
vivado [14]
The answer is zero point four three

You could also write this answer as 0.43
7 0
3 years ago
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