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77julia77 [94]
3 years ago
14

Use the Law of Sines to find mZY.

Mathematics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

Step-by-step explanation:

recall law of Sines   :) the same as before  Sin(A) /a = Sin(B) / b

[ when you see it a lot.. you'll remember it  :D ]

for this problem  Z =A=123  and a = 30

Y=B and b =14

Sin(123) / 30 = Sin(B) / 14

14 * 0.0279556 = Sin(B)

0.391379 = Sin(B)

arcSin(0.391379 ) = arcSin ( Sin (B) )

23.040 = B

Y = 23.0°

are you seeing how to do these?  so you could on a test?

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a local company uses 13 1/2 tons of paper in one week. It recycles about 1/3 of its waste. how many tons of paper does the compa
bogdanovich [222]

Answer:

4 1/2 tons of recycled paper

Step-by-step explanation:

13.5/3 = 4.5 or 4 1/2

3 0
2 years ago
the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function
Likurg_2 [28]

The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about area here:

brainly.com/question/27683633

#SPJ4

3 0
2 years ago
A cube has a volume of 2197 m^3. Its surface is to be painted. Each can of paint covers about 40 m^2. How many cans of paint are
Gelneren [198K]
<em>Volume= a³</em>
<em>a=edge</em>
<em>2197 = a³</em>
<em>=> a=13 m</em>
<em>Surface area=6a²=6*13²=6*169=1014 m²</em>
<em>\frac{1014}{40} = 25,35 ≈ 26</em>
<em>=> <u>26 cans needed</u></em>
8 0
3 years ago
The histograms show the number of new subscribers in one month by age group for three newspaper. which statement is best support
natita [175]
I think it’s A cus it’s more general info about it that sums up the difference of the chronicle to the other ones i’m not sure tho
7 0
3 years ago
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel
serious [3.7K]

Complete Questions:

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.

a. 40

b. 48

c. 56

d. 64

Answer:

a. 0.35

b. 0.43

c. 0.49

d. 0.54

Step-by-step explanation:

(a)

The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.  

Let s be the sample space of all integer not exceeding 40.

The total number of ways to select 6 numbers from 40 is |S| = C(40,6).

Let E be the event of selecting none of the correct six integers.

The total number of ways to select the 6 incorrect numbers from 34 numbers is:

|E| = C(34,6)

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is  

P(E) = \frac{|E|}{|S|}

         = \frac{C(34, 6)}{C(40, 6)}\\\\= \frac{1344904}{3838380}\\\\=0.35

Therefore, the probability is 0.35

Check the attached files for additionals  

8 0
3 years ago
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