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3 years ago

SOMEONE PLEASE HELP ME!!!!!!!

Mathematics

1 answer:

OleMash [197]3 years ago

4 0

Answer:

Step-by-step explanation:

$\frac{57}{40.3}=\frac{23}{QR} \\$

cross multiply

57(QR)=926.9

QR=16.26...

round to nearest tenth

QR=16.3

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A student finished 8 of her homework problems in class. If the ratio of problems she finished to problems she still had left was

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Answer:

10 problems

Explanation:

The ratio can be used to find the number of problems left. Then, you can add all the problems together to find your final answer.

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Simplify the expression using long division. (10x2 – 85x – 10) ÷ (x – 8) Question 7 options: quotient 10x – 5 and remainder –50

Anna [14]

Answer:

The quotient is (10x - 5) and the reminder is -50 ⇒ 1st answer

Step-by-step explanation:

* Lets solve the long division by easiest way

∵ (10x² - 85x - 10)/(x - 8)

∵ (10x² - 85x - 10) is the dividend

∵ (x - 8) is the divisor

- Divide the first term of the dividend by the first term of the divisor

∴ 10x² ÷ x = 10x ⇒ first term of the quotient

- Multiply 10x by the the divisor

∴ 10x(x - 8) = 10x² - 80x

- Subtract the answer from the dividend

∴ (10x² - 85x - 10) - (10x² - 80x) =

# 10x² - 10x² = 0

# -85x - -80x = -85x + 80x = -5x

# -10

∴ (10x² - 85x - 10)/(x - 8) = 10x + (-5x - 10)/(x - 8)

* Repeat the same steps again with the new dividend -5x - 10

- Divide the first term of the dividend by the first term of the divisor

∴ -5x ÷ x = -5 ⇒ second term of the quotient

- Multiply -5 by the divisor

∴ -5(x - 8) = -5x + 40

- Subtract the answer from the dividend

∴ (-5x - 10) - (-5x + 40) =

# -5x - -5x = -5x + 5x = 0

# -10 - 40 = -50

∴ (-5x - 10)/(x - 8) = -5 + -50/(x - 8)

∴ (10x² - 85x - 10)/(x - 8) = 10x - 5 + -50/(x - 8)

- The quotient is the answer of the division

∴ The quotient is (10x - 5) and the reminder is -50

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Answer:

Area of the walkway = 8x + 24

Step-by-step explanation:

Area of the total backyard = $l\times b$

Area of total backyard = $(x+6)\times (x+4) = x^{2} +10x + 24$

Now, Area of the rectangular garden = $l\times b$

Area of the rectangular garden = $x (x+2) = x^{2} + 2x$

Now area of the walkway poured with concrete = Area of the backyard - Area of the rectangular garden

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= $x^{2} + 10x +24 - x^{2} -2x$

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3 years ago

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Answer:

It is already the farthest that can be

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fomenos

Answer:

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Step-by-step explanation:

y-y1=m(x-x1)

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