Answer:
b
Step-by-step explanation:
Hope this helpsss :)
Answer:
area of the original square = 36 in²
Step-by-step explanation:
given data
one side is increased = 9 inches
other side is decreased = 2 inches
area of the resulting rectangle = 60 in²
solution
we consider here x as the length of any one side
and
longer side of the resulting rectangle = x + 9
and
the shorter side x - 2
so that area of this rectangle is (s+9) × (s-2) = 60 in²
standard form of equation is x² + 7x - 18 = 60 .....................1
it will be
x² + 7x - 78 = 0
(s+13) (s-6) = 0
so that here x = -13
and x = 6
here we Discard x = -13 because the side length cannot be negative.
so x = 6
and area of the original square = 36 in²
we are given
f(x)=[x=1]
where bracket means ceiling functions
we know that
Ceiling function returns the least value of the integer that is greater than or equal to the specified number
so, we can check each options
option-A:
At x=-4:
f(x)=[-4-1] =-5
For x<-3:
Let's assume
x=-3.1
f(x)=[-3.1-1] =[-4.1]=-5
so, this interval is TRUE
option-B:
At x=-2:
f(x)=[-2-1] =-3
For x<-1:
Let's assume
x=-1.1
f(x)=[-1.1-1] =[-2.1]=-3
so, this is FALSE
Answer:
y = 3x - 1
Step-by-step explanation:
Let's start with the two points.
y = mx + b
-19 = -6m + b
5 = 2m + b
Subtract the first from the second.
24 = 8m
m = 3
5 = 2*3 + b
b = -1
Don’t know maybe uses online resource form a teacher?
