We are given an arithmetic sequence with
First term, a₁ = 6
Second term, a₂ = 2
Therefore the common difference is d = -4.

The n-th term is
$a_{n} = a_{1} + (n-1)d \\ a_{n} = 6 - 4(n-1), \, for \, n \ge 1$

Answer:
$a_{n} = 6 - 4(n-1);$ all integers where n ≥ 1

8 0

3 years ago

" In the nine markets (in Chang'an) they set up bazaars, Their wares separated by type, their shop rows distinctly divided. Ther

Alisiya [41]

Answer: Chinese cities included prosperous merchants and vibrant trade.

Explanation:

From the text it is seen that there was a lot of trade going on in the city. Everywhere one goes there are hundreds of shops. This means that trade must have been very vibrant.

Cities with vibrant trade make for trading hubs that will attract people from far and wide. This would therefore give merchants the opportunity to become very successful and prosperous from selling their wares.

5 0

3 years ago