Answer: tye
Step-by-step explanation:
Answer:
4 seconds
Step-by-step explanation:
Given : 
To Find: How many seconds does it take for the golf ball to hit the ground?
Solution :
Since we are given an equation : 
Where H denotes height
t denotes the number of seconds elapsed since the ball was hit.
When he golf ball to hit the ground at that time the height becomes 0
So, put H = 0 in the equation






Thus it take 4 seconds for the golf ball to hit the ground
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
You need to work backwards
if it is no more than 9 units away from 8
thus x must be 8-9<x<8+9 solving -1<x<17
so the answer is 4.
Answer:
y = 7x + 12
Step-by-step explanation:
Slope (m) = 7
Line is passing through the point (0, 12)
y-intercept (b) = 12
Equation of line in slope-intercept form is given as:
