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adelina 88 [10]

3 years ago

9

Which statement is true? All squares are rectangles. All quadrilaterals are rectangles. All parallelograms are rectangles. All r

ectangles are squares. Select each correct answer.

1 answer:

azamat3 years ago

4 0

Answer:

all squares are rectangles is true

Step-by-step explanation:

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Help me please new topic

Alla [95]

Answer:

B?

Step-by-step explanation:

3 0

2 years ago

4.5w=5.1w-30, how do I solve it

Gala2k [10]

First you have to get the same variables on one side so you’d subtract 5.1w from both sides, making the equation -0.6w = -30

then you want to single out the variable, diving -0.6 on both sides making the new equation and the answer w = 50

hope this helps!

5 0

4 years ago

Read 2 more answers

Can you help me .....................?

aniked [119]

Answer:

11/18

Step-by-step explanation:

The desired probability is the sum of ...

... (probability of choosing a coin) × (p(heads) on that coin)

Since the coins are chosen at random, we assume the probability of choosing a given coin is 1/3. Then ...

... p(heads) = (1/3)·(1/2) + (1/3)·1 + (1/3)·(1/3) = 1/6 + 1/3 + 1/9 = (3 +6 + 2)/18

... p(heads) = 11/18

5 0

3 years ago

What is a true statement about negative exponents?

Nadya [2.5K]

Answer:

Raising something to a negative exponent is just taking the reciprocal of the amount.

Step-by-step explanation:

Let's assume that you wanted to know what $x^{-2}$ is.

To find it, you would take the reciprocal of the x amount. So $x^{-2}$ becomes $\frac{1}{x^{2}}$ .

This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So $a^{3}$ would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase $a^{3}$ to $a^{5}$ , you would have to multiply a with $a^{3}$ two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease $a^{5}$ to $a^{2}$ , you would have to divide $a^{5}$ by a 3 times.

If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: $\frac{1}{a^{3}}$ means that you are dividing 1 by a 3 times.

Hope this helps.

3 0

3 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago