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choli [55]
3 years ago
9

Can someone please help meeeee on this question?!!!!!!!!

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0
The length of jk is 10
You might be interested in
(2*)2-3×2*+2=0<br>4m-15°(×)m+75°​
Valentin [98]

Answer:

First, we write the augmented matrix.

⎡

⎢

⎣

1

−

1

1

2

3

−

1

3

−

2

−

9

|

8

−

2

9

⎤

⎥

⎦

Next, we perform row operations to obtain row-echelon form.

−

2

R

1

+

R

2

=

R

2

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

3

−

2

−

9

|

8

−

18

9

⎤

⎥

⎦

−

3

R

1

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

The easiest way to obtain a 1 in row 2 of column 1 is to interchange \displaystyle {R}_{2}R

​2

​​  and \displaystyle {R}_{3}R

​3

​​ .

Interchange

R

2

and

R

3

→

⎡

⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

Then

−

5

R

2

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

15

57

⎤

⎥

⎦

−

1

57

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

1

|

8

−

15

1

⎤

⎥

⎦

The last matrix represents the equivalent system.

x

−

y

+

z

=

8

y

−

12

z

=

−

15

z

=

1

Using back-substitution, we obtain the solution as \displaystyle \left(4,-3,1\right)(4,−3,1).First, we write the augmented matrix.

⎡

⎢

⎣

1

−

1

1

2

3

−

1

3

−

2

−

9

|

8

−

2

9

⎤

⎥

⎦

Next, we perform row operations to obtain row-echelon form.

−

2

R

1

+

R

2

=

R

2

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

3

−

2

−

9

|

8

−

18

9

⎤

⎥

⎦

−

3

R

1

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

The easiest way to obtain a 1 in row 2 of column 1 is to interchange \displaystyle {R}_{2}R

​2

​​  and \displaystyle {R}_{3}R

​3

​​ .

Interchange

R

2

and

R

3

→

⎡

⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

Then

−

5

R

2

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

15

57

⎤

⎥

⎦

−

1

57

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

1

|

8

−

15

1

⎤

⎥

⎦

The last matrix represents the equivalent system.

x

−

y

+

z

=

8

y

−

12

z

=

−

15

z=1

Using back-substitution, we obtain the solution as \displaystyle \left(4,-3,1\right)(4,−3,1).

7 0
2 years ago
One serving of punch is 250 ml.will ten servings fit in a 2 liter bowl
Oliga [24]
First, we should find how many total milliliters we have by multiplying 250 mL by 10 servings to get 2500 mL. Then, we can convert 2500 mL to liters because 1000 mL equals 1 liters (2500/1000=2.5 L). Then since the bowl can only have 2 liters of punch, then 10 servings will not fit.

Hope this helps
5 0
3 years ago
Please help me with this
4vir4ik [10]

Answer:

3, 8, 12, 12, 14, 20, 21, 23, 26, 34

stem         leaf

0               3     8

1                 2     2       4               (you have 12,12,14)

2                0      1       3        6    ( numbers 20,21,23,26)

3                 4                               ( number 34)

6 0
3 years ago
Read 2 more answers
Solve the Equation. 20x + 12 ≥ 14x + 30 A. x ≥ 7 B. x ≤ 7 C. x ≥ 3 D. x ≤ 3
Tamiku [17]

Answer:

x≥3

Step-by-step explanation:

Treat the ≥ symbol like it is an equals sign. First, subtract 14x from each side to get 6x+12≥30. Then, Subtract 12 from each side to get 6x≥18. I will let you solve the rest :)

8 0
3 years ago
Read 2 more answers
Solve this equation: -88=5y-13
nadya68 [22]

Answer:

y=-15

Step-by-step explanation:

4 0
3 years ago
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