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ivann1987 [24]
3 years ago
15

Use the discriminant to determine all values of k which would result in the graph of the equation

Mathematics
1 answer:
kirill [66]3 years ago
5 0

Answer:

sauce is 177013

Step-by-step explanation:

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Luke called a repairman to fix the furnace at his cabin. The repairman charged $35 per hour plus a fee of $25 for the service ca
Marizza181 [45]

Answer:

The answer is A.

Step-by-step explanation:

To find the value you have to know how many hours the repairman took to repair. Then after you find how many hours he took multiply the hours by 35 than add 25.

So the equation would look like  35x hr+25 =

hr=hours

6 0
3 years ago
Eighth grade
Natasha2012 [34]

Answer:

1/4

Step-by-step explanation:

in the graph, the value of x goes up four before the y value goes up one

7 0
3 years ago
Use power reduction formula to rewrite the equation in terms of cosine: cos^2x sin^4 x
Mashutka [201]
Cos^2(x) sin^4(x) = 1/2(1 + cos(2x)) * (1/2(1 - cos(2x))^2 = 1/2(1 + cos(2x)) * 1/4(1 - 2cos(2x) + cos^2(2x)) = 1/8(1 + cos(2x))(1 - 2cos(2x) + 1/2 + 1/2cos(4x)) = 1/16(1 + cos(2x))(3 - 2cos(2x) + cos(4x)) = 1/16(3 - 2cos(2x) + cos(4x) + 3cos(2x) - 2cos^2(2x) + cos(2x)cos(4x)) = 1/16(3 + cos(2x) + cos(4x) - (1 + cos(4x)) + 1/2cos(6x) + 1/2cos(2x)) = 1/32(4 + 3cos(2x) + cos(6x))
6 0
3 years ago
Help please! I already tried doing this but I didn't get the answer right, and I don't know where I went wrong
Sladkaya [172]

I think factorizing everything you can first will make the simplification ... well, simpler.

\dfrac{x^2 - 3x}{x^2 + 13x + 36} \div \dfrac{x^2+7x}{x^2+16x+63} = \dfrac{x(x-3)}{(x+4)(x+9)} \div \dfrac{x(x+7)}{(x+7)(x+9)}

The factors of x+7 in the second rational expression cancel:

\dfrac{x^2 - 3x}{x^2 + 13x + 36} \div \dfrac{x^2+7x}{x^2+16x+63} = \dfrac{x(x-3)}{(x+4)(x+9)} \div \dfrac{x}{x+9}

Now, use the property

\dfrac ab \div \dfrac cd = \dfrac ab \times \dfrac dc

(this is the property of multiplication having to do with multiplicative inverse, or "inverting the divisor" as the question calls it) to write

\dfrac{x^2 - 3x}{x^2 + 13x + 36} \div \dfrac{x^2+7x}{x^2+16x+63} = \dfrac{x(x-3)}{(x+4)(x+9)} \times \dfrac{x+9}x

and we see some more cancellation, namely of the factors of x and x+9.

\dfrac{x^2 - 3x}{x^2 + 13x + 36} \div \dfrac{x^2+7x}{x^2+16x+63} = \boxed{\dfrac{x-3}{x+4}}

6 0
2 years ago
In the diagram below, BD is parallel to XY. what is the value of y?
melisa1 [442]

I can't see the diagram sorry.

Step-by-step explanation:

Is there supposed to be a picture attached?

8 0
3 years ago
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