Answer: r_max = 1.75m
Step-by-step explanation:
Below is a rather brief analysis to solving this problem.
The phone starts sliding when along incline,
when F_net = m g sin(theta) - fs_max = 0
and fs_max = us N = us m g cos(theta)
m g sin(theta) - us m g cos(theta) =
us = tan(theta) = tan38 = 0.781
On merry - go - round,
fs_max = us N = us m g
Using F = m a
fs_max = m w^2 r_max and w = 2pi / T
us m g = m (2 pi / T)^2 (r_max)
0.781 x 9.81 = (2 pi / 3)^2 (r_max)
r_max = 1.75 m
cheers i hope this helped !!
1. To solve this problem, you must keep on mind the followinwg information:
You know that, by definition, an irrational number is a number that cannot be expressed as a fraction.
2. Therefore, the correct answer is the option D.
3. To verify the answer you have:
∛16=2.51
As you can see, the result is 2.51 and the decimal number 2.51 cannot be expressed as a fraction.
The answer is 0.009.
Hope this helps!:)
F(x)=2x+3-(x+10)
0=2x+3-x-10
0=x-7
-x=-7
x=7
Answer:
2 metre
Step-by-step explanation:
let the width around the field be x metre
then (16+2x)(10+2x)-16×10=120
160+32x+20x+4x²-160=120
4x²+52x-120=0
or x²+13x-30=0
x²+15x-2x-30=0
x(x+15)-2(x+15)=0
(x+15)(x-2)=0
either x+15=0,
x=-15 (Rejected being negative)
or x-2=0
x=2 metre
