First we would need to find the portion of the gymnasium to the blueprint to do that please do this:
88/5.5 = 16
The length divided by the blueprint's length
Since we know that the gymnasium is 16 times the blueprint, to find the width divide 16 to 76:
76/16 = 4.75
The width divided by the 16 times
The width of the blueprint is 4.75 inches
Answer with Step-by-step explanation:
The radius of the bull’s-eye of the dartboard is 8 inches.
The radius of each concentric circle is 8 inches more than the radius of the circle inside it.
Radius of first circle=8 in.
Radius of second circle=16 in.
Radius of third circle=24 in.
Radius of fourth circle=32 in.
Area of C=Area of the third circle-Area of second circle
= π×24×24-π×16×16
= 320π sq. in.
Total area of dartboard=Area of fourth circle=π×32×32
=1024π sq. in.
P( the dart will hit in area C)= area of c/total area of dart board
=320π/1024π
= 5/16
Hence, correct option is:
B.5/16
Answer:
The correct answer is option A. Base = 11 cm and height = 13 cm
Step-by-step explanation:
It is given that, height of a triangle is 2 cm more than its base.Then height is increased by 2 cm.Then the area of triangle becomes 82.5 cm²
<u>To find the base an d height of original triangle</u>
Let x be the original base 'b' then the height h = x + 2
New height h = x + 2 + 2 = x + 4
Area = bh/2
82.5= (x(x + 4)/2
165 = x² + 4x
x + 4x - 165 = 0
Solving we get x = 11 and x = -15
Take positive value x = 11
Therefore base = 11 and height = x + 2 = 13 cm
The correct answer is option A. Base = 11 cm and height = 13 cm
Answer:
19
Step-by-step explanation:
-8+8=0
0+19=19
Hope it helps.
