2 1/4 x 1 1/2 x 5/3?????
1 answer:
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<h2>Answer:</h2><h2>Gavin would be expected to run during 36.5 miles during his 11th week of the training plan</h2>
Step-by-step explanation:
In the first week of his running plan,the number of miles covered = 5 miles
Weekly mileage will increase by 3.5 miles every week.
At the end of second week, the number of miles covered = 5 + 3.5 = 8.5
At the end of third week, the number of miles covered = 8.5 + 3.5 = 12
The series is 5, 8.5, 12, ...
Consider this as an AP, where a = 5, d = 3.5
By formula,
Substituting the values in the above equation, we get
= 5 +(9)3.5
= 5 + 31.5
=36.5 miles.
Gavin would be expected to run during 36.5 miles during his 11th week of the training plan
Answer:
a
b
The nutritionist does not have sufficient evidence to reject the writers claim
Step-by-step explanation:
From the question we are told that
The population mean is
The sample size is
The sample mean is
The standard deviation
The level of significance is
Now the
Null Hypothesis is
Alternative Hypothesis is
generally the degree of freedom is mathematically represented as
For a significance level of 0.05 and 19 degrees of freedom, the critical value for the t-test is 2.093. This is obtain from the t-distribution table
The test statistic is mathematically evaluated as
substituting values
Since the test statistic is below the critical value then the Null hypothesis can not be rejected
So we can conclude that the nutritionist does not have sufficient evidence to reject the writers claim