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Lina20 [59]
3 years ago
15

1 2 3 4 5 6 7 8 9 10

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0
Enjoy baby ganyuuuuuuuuuu

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Given cos theta=24/25 and is located in Q3, Evaluate the rest of the trigonometric functions:. 1. sin theta=. 2. tan theta=. 3.
Tom [10]
CosФ=24/25

Sin Ф=7/25 CoseceФ=25/7
TanФ=7/24 cotФ=24/7
SecФ=25/24
7 0
3 years ago
Is (0, 3) a solution to the inequality y > 2x + 3?
Doss [256]

Answer:

Step-by-step explanation:

6 0
3 years ago
Find the function f (x) =ax2 + bx+ c whose graph contains the points (1, 2), (-2,-7), and (2, -3). Write the system of equations
yan [13]

what grade you r?????....

3 0
3 years ago
Which of the following sjows the correct key features of the graph?
sammy [17]

Answer:

Step-by-step explanation:

y = x^2 - x - 2 is a quadratic function.  It's easily factorable:  y = (x + 1)(x - 2).  Setting this result equal to zero yields the x-intercepts:  -1 and 2.  This matches the x-intercepts shown on the graph.

The axis of symmetry,  x = -b/(2a), derived from the coefficients 1, -1 and -2 of this particular function, is x = 1/2.  This x = 1/2 is also the x-coordinate of the vertex.  To find the y-coordinate of the vertex, we evaluate y = x^2 - x - 2 at x = 1/2, obtaining:

y = (1/2)^2 - (1/2) - 2, or y = 1/4 - 1/2 - 2, or -2 1/4.  This does not quite agree with the y value (-2) shown in the diagram, but is close.

4 0
3 years ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir
Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

\sigma = \sqrt{484} = 22

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

M = z*\frac{\sigma}{\sqrt{n}}

5 = 1.96*\frac{22}{\sqrt{n}}

5\sqrt{n} = 43.12

\sqrt{n} = \frac{43.12}{5}

\sqrt{n} = 8.624

(\sqrt{n})^{2} = (8.624)^{2}

n = 74.4

We need a sample size of at least 75.

6 0
3 years ago
Read 2 more answers
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