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Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

6 0

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Express the number 24 as the product of its prime number

igor_vitrenko [27]

Answer:

Prime factors of 24 = 2*2*2*3.

Step-by-step explanation:

24 / 2 = 12

12 / 2 = 6

6 / 2 = 3

Prime factors of 24 = 2*2*2*3.

3 0

3 years ago

What are 4 equivalent expressions for 15x + 25x?

GalinKa [24]

(1). (45x + 75x) / 2
(2). (30x + 50x) / 2
(3). 40x
(4). (60x - 40x) * 2

8 0

4 years ago

Round 89.96 to the nearest tenth

miv72 [106K]

Your answer is 90. Hope that helps!

7 0

3 years ago

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If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

4 years ago

Which products reslut in a difference of squares? check all that apply.

algol13

Answer:

A,C,D,E

Step-by-step explanation:

If you plug in any random number and you graph it for each one of the problems the answer will change

8 0

3 years ago

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