The population you gave isn't formatted correctly so I'll solve the problem assuming you mean 103,500.
First we find the number of males from the percentage given:
0.56 * 103500 = 57960 males
Subtract the number of males from the total population to get the number of females:
103500 - 57960 = 45540 females
You could solve the problem by finding the percentage of females first. Since there are 56% males, that means there are 100-56 = 44% females.
0.44 * 103500 = 45540
The answer is 45540.
The value of

,

, and

for each schools is given in the first picture below.

is the lower quartile

is the median

is the upper quartile
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
Answer:
The correct answer is A I believe . . .
Answer: 5,984 ÷ 32 = 0,187
Ok done. Thank to me :>
Answer:
Period =½
Equation of midline, y=0
Maximum =2
Minimum=-2
Step-by-step explanation:
The given function is

The period is given by:

The equation of the midline is y=0 since there is no vertical shift
The amplitude of this function is 2 so the range is -2≤y≤2.
Hence the maximum value is 2 and minimum value is -2