There both in the thousands place
No, because if you substitute (4, -2) into x and y in each equation, they are not the same as the value on the right side of the equation.
2(4) + 4(-2) = - 2
8 + -8 = -2
0 = -2 <---- this is not correct.
-4(4) + -2 = -14
-16 + -2 = -14
-18 = -14 <----- this is not correct.
Answer:
-a^2 + -a + 12
Step-by-step explanation:
Expand the following:
(3 - a) (a + 4)
(3 - a) (a + 4) = (3) (a) + (3) (4) + (-a) (a) + (-a) (4):
-a a + 3 a - 4 a + 3 4
3×4 = 12:
-a a + 3 a - 4 a + 12
-a a = -a^2:
-a^2 + 3 a - 4 a + 12
Grouping like terms, -a^2 + 3 a + 4 (-1) a + 12 = -a^2 + (3 a - 4 a) + 12:
-a^2 + (3 a - 4 a) + 12
3 a - 4 a = -a:
Answer: -a^2 + -a + 12
The value of tan3x must be greater than the value of cos3x, because it is subtractable by a lesser value.
