How to simplify y to the 7th power×y to the 2nd power

Suppose 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at

ANEK [815]

Answer:

We conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

Step-by-step explanation:

We are given that 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at a fourth grade level.

Further suppose 135 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not "do math" at a fourth grade level (like fractions).

Let $p_1$ = proportion of college students who would be embarrassed to truthfully admit they could not read at a fourth grade level.

$p_2$ = proportion of college students who would be embarrassed to truthfully admit they could not "do math" at a fourth grade level.

So, Null Hypothesis, $H_0$ : $p_1-p_2$ = 0 or $p_1= p_2$ {means that there is not any significant difference in the proportion of all college students who would be embarrassed by these two admissions}

Alternate Hypothesis, $H_A$ : $p_1-p_2$ $\neq$ 0 or $p_1\neq p_2$ {means that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions}

The test statistics that would be used here Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of college students who would be embarrassed to admit they could not read at a fourth grade level = $\frac{462}{500}$ = 0.924

$\hat p_2$ = sample proportion of college students who would be embarrassed to admit they could not "do math" at a fourth grade level = $\frac{135}{500}$ = 0.27

$n_1$ = sample of college students = 500

$n_2$ = sample of college students = 500

So, test statistics = $\frac{(0.924-0.27)-(0)}{\sqrt{\frac{0.924(1-0.924)}{500}+\frac{0.27(1-0.27)}{500} } }$

= 28.28

The value of z test statistics is 28.28.

Also, P-value of the test statistics is given by;

P-value = P(Z > 28.28) = Less than 0.0005%

Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

5 0

4 years ago

Can someone help me on my algebra 1 ?

kramer

Sure comment down the question.

4 0

3 years ago

If y varies directly as x, and y = 15 as x = -3, find y for the x-value of 4.

NeX [460]

Y = kx
15 = -3k
k = -5

so if x = 4
y = kx
y = (-5) (4) = - 20

answer

y = -20 when the x = 4.

3 0

3 years ago

Find all solutions in the interval [0, 2π).

jekas [21]

First you must know that for remarkable angles: cos (0) = 1, cos (π) = - 1, cos (π / 2) = 0, cos (3π / 2) = 0, cos (2π) = 1. Then, by simple substitution in the given formula, you can find the solutions of x. Which for the interval [0, 2π) are: x = π, x = pi divided by two and x = three pi divided by two.Attached solution.

4 0

3 years ago

Read 2 more answers

Factor this polynomial: x^2 + 6x + 9 (x+3)(x+3) (x-3) (x-3) (x-3) (x+3) (x+3) (x-3)

Lyrx [107]

Answer:

(x+3)(x+3)

Step-by-step explanation:

1) this polynomial is in the form of ax^2+bx+c

c=9

b=6

a=1

what*what=c(9)

and what+what=b(6)

3 is the answer to both questions:

now substitute "3x" in place of "6"

x^2+3x+3x+9

split in 2 groups:

group a) (x^2+3x)

gcf of group a=x

x(x+3)

group b) (3x+9)

gcf of group b=3

3(x+3)

combine the numbers OUTSIDE the parantheses

so

(x+3)(x+3)

6 0

3 years ago

Read 2 more answers

How to simplify y to the 7th power×y to the 2nd power​

How to simplify y to the 7th power×y to the 2nd power