You have to round it to the nearest hundreds
Answer: ![\sqrt[3]{6n}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B6n%7D)
Step-by-step explanation:
We have the following expression:
Which can be written as follows:
Multiplying the exponents:
Writing in radical form we finally have the result:
I don't exactly know what a net is, but I can figure out the surface area (maybe). When you put this pattern together, you have to make a couple of assumptions.
First of all the 2 triangles are connected to a base that's 8 by 13.
Base
The area of the base = 8 * 13 = 104 square feet.
Two Triangles.
The area of any triangle is
Area = 1/2 b * h
Area = 1/2 *12 * 5
Area = 30 square feet. There are 2 triangles so ...
The total area of both is 60 square feet.
Overlap
Now we come to the tough part. how big is it from the first dotted line to the second one?
The answer is 5. But why? Well the 5 comes from the the length of the side that has to be covered by this pattern. The 5 is part of the triangle.
How far across is the dotted line? The answer is 8. Why again? That's the width of the whole prism or pattern.
So the area between the two dotted lines is 5 * 8 = 40
Finally the area over the 12.
The question is how far is it from the second dotted line to the last boundary? The answer is 12. And it's width is 8
So the area = 12 * 8 = 96
Total area
96 + 60 + 40 + 104 = 300 square feet.
Answer:
the area of the circle: 25π
Step-by-step explanation:
45/4 π = 11.25π
9/10π = 0.9π
11.25π / 0.9π = x / 2π .... 360° = 2π
x = (11.25π x 2π) / 0.9π = 25π
Answer:
2232.48 meters
Step-by-step explanation:
From the diagram:
Radius of semicircle = 74
Length of straightway on each side = 1000
The length of school track :
Straightway on each side = 2 * 1000 m = 2000m
Length of semicircle = πr/2
Length of both semicircle = 2 * 3.142 * 74 /2 = 232.47785
Total Length = ( 2000 + 232.47785) = 2232.48 meters
