Answer:
6.25 % of area of Large triangle = area of smallest triangle
Step-by-step explanation:
Area of large triangle L = (1/2)*base*height
L = (1/2)*(44 m)* h
L = 22*h square m.
2nd equilateral triangle area: S =(1/2)*(22 m)*(0.5h)
S = 5.5*h sq. m.
3rd smallest equilateral triangle area : T = (1/2)*(11 m)*(0.25h)
T = 1.375*h sq. m
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Find percent P where T = P* L, 1.375*h = P * 22*h
P = 6.25% = 0.0625
Answer:
y = x for x ≥ 0 and y = - x for x < 0
Step-by-step explanation:
The absolute value function is written as y = |x| and it is defined as following
|x| = x when, x ≥ 0 and |x| = - x when, x < 0.
Therefore, the equations for the domain of x ≥ 0 is y = x
and the equation for the domain of x < 0 is y = - x (Answer)
9514 1404 393
Answer:
1.1 quarts
Step-by-step explanation:
Let x represent the amount to be added, in quarts. Then the amount of anti-freeze in the resulting solution is ...
0.20(8) + 1.00(x) = 0.30(8 +x)
0.70x = 0.10(8) . . . . . . subtract 0.20(8)+0.30(x)
x = 8/7 . . . . . . . . . . . . . divide by the coefficient of x
x ≈ 1.142857 ≈ 1.1
About 1.1 quarts of pure antifreeze must be added.
You need to multiply the Length of the pool by the width of the pool so the setup would be like this:
A = 30 1/3 x 12 1/2
and the answer would be approximately 379.17 <span />
35% because u need to multiply them all