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AnnZ [28]
3 years ago
15

Is the function odd, even or neither?​

Mathematics
1 answer:
iren2701 [21]3 years ago
7 0
Answer is: even

This function’s graph is symmetric with respect to the y-axis therefore, this function is even.
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Six students are being grouped into three pairs to work on a science lab. how many different combinations of three pairs are pos
pychu [463]

We want to select 3 pairs of people from a group of 6.

We use the formula:

n! / (r! * (n -r)!)

where n = 6 and r = 2

combinations = 6! / (2! * 4!) =

combinations = 6 * 5 / 2

combinations = 15


Source:

1728.com/combinat.htm




4 0
4 years ago
Help i'm confused.....
AlladinOne [14]

Answer:

the fourth one 2(4+n)

Step-by-step explanation:

you do 4+n

whatever the sum is you multiply that by 2

lmk if that helps

5 0
3 years ago
Money is put into two accounts. Account A earns 3.5% interest annually, and account B eanrs 2.6% interest annually. Assuming $20
natita [175]

Answer:

$3360 combined. $1560 from acct b and $2100 from acct a

3 0
3 years ago
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nekit [7.7K]

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~ Zachary

4 0
3 years ago
You have two biased coins. Coin A comes up heads with probability 0.1. Coin B comes up heads with probability 0.6.However, you a
Andrews [41]

Answer:

The probability that our guess is correct = 0.857.

Step-by-step explanation:

The given question is based on A Conditional Probability with Biased Coins.

Given data:

P(Head | A) = 0.1

P(Head | B) = 0.6

<u>By using Bayes' theorem:</u>

P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}

We know that P(B) = 0.5 = P(A), because coins A and B are equally likely to be picked.

Now,

P(Head) = P(A) × P(head | A) + P(B) × P(Head | B)

By putting the value, we get

P(Head) = 0.5 × 0.1 + 0.5 × 0.6

P(Head) = 0.35

Now put this value in P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)} , we get

P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}

P(B|Head) = 0.6 \times \frac{0.5}{0.35}

P(B|Head) = 0.857

Similarly.

P(A|Head) = 0.857

Hence, the probability that our guess is correct = 0.857.

7 0
4 years ago
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