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Wittaler [7]
3 years ago
7

1

Mathematics
1 answer:
KonstantinChe [14]3 years ago
6 0
<h2>                     QUESTION # 1</h2>

Answer:

  • Total distance = 21 units (meters)
  • The average speed = 7 meter per second.

Step-by-step explanation:

To Determine:

If the whole run took the bug 3 seconds, what was its average speed?

Information Fetching and Solution Steps:

  • A beetle was running along a number line.
  • The beetle ran from 4 to 25.

Let suppose each unit on a number line represents 1 meter.

As the beetle ran from 4 to 25, so

the distance covered by beetle is:

                                           25 - 4 = 21 units. i.e. 21 meters

As the average speed can be determined by dividing the total distance by the total time, so

The average speed = total distance / total time

as

Total distance = 21 units (meters)

Total time = 3 seconds

so

The average speed = total distance / total time

                                 = 21/3

                                 = 7 meter per second

Therefore, the average speed = 7 meter per second.

                       

<h2>                       QUESTION # 2</h2>

Answer:

  • Total distance = 54 units (meters)
  • The average speed = 6 meter per second.

Step-by-step explanation:

To Determine:

If the whole run took the bug 9 seconds, what was its average speed?

Information Fetching and Solution Steps:

  • A beetle was running along a number line.
  • The beetle ran from 24 to 78.

Let suppose each unit on a number line represents 1 meter.

As the beetle ran from 24 to 78, so

the distance covered by beetle is:

                                         78 - 24 = 54 units. i.e. 54 meters

As the average speed can be determined by dividing the total distance by the total time, so

The average speed = total distance / total time

as

Total distance = 54 units (meters)

Total time = 9 seconds

so

The average speed = total distance / total time

                                 = 54/9

                                 = 6 meter per second

Therefore, the average speed = 6 meter per second.

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Step-by-step explanation:

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If you multiply the upper equation or down equation by one, you will be able to eliminate the x variable.

-1( 2x + 3y) = -1(8)     New equation:   -2x -3y  = -8.

Add the new equation you got  by multiplying the top equation by -1 to the bottom equation.

Add them:     -2x -3y = -8

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Find the product. Simplify your answer.<br> -5 • 9t<br> 7s 7
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Answer:

-13            

 ——— = -0.20635  

 63            

Step-by-step explanation:

Step  1  :

           7

Simplify   —

           9

Equation at the end of step  1  :

 4    7

 — -  —

 7    9

Step  2  :

           4

Simplify   —

           7

Equation at the end of step  2  :

 4    7

 — -  —

 7    9

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       7  

     The right denominator is :       9  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

7 1 0 1

3 0 2 2

Product of all  

Prime Factors  7 9 63

     Least Common Multiple:

     63  

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 9

  Right_M = L.C.M / R_Deno = 7

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      4 • 9

  ——————————————————  =   —————

        L.C.M              63  

  R. Mult. • R. Num.      7 • 7

  ——————————————————  =   —————

        L.C.M              63  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

4 • 9 - (7 • 7)     -13

———————————————  =  ———

      63            63  

Final result :

 -13            

 ——— = -0.20635  

 63            

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