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noname [10]
3 years ago
8

A7DF is the hexadecimal representation for what bit pattern?

Computers and Technology
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

1010 0111 1101 1111

Explanation:

A = 10 in decimal = 1010 in binary

7 = 7 in decimal = 0111 in binary

D = 13 in decimal = 1101 in binary

F = 15 in decimal = 1111 in binary

Therefore 0xA7DF = 1010 0111 1101 1111 in binary

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Write a JAVA program containing a method called hasEight(), which takes an int as input and returns true if the number contains
skelet666 [1.2K]

Here's my code for that, consider it under the WTFPL (http://www.wtfpl.net/). Here is a pastebin of the code, as to avoid text formatting. (Link: https://pastebin.com/S3BDGxqm Raw: https://pastebin.com/raw/S3BDGxqm)

package javaapplication6;

import java.util.Scanner;

public class JavaApplication6 {

   

   public static void main(String[] args) {

       

       Scanner myScanner = new Scanner(System.in);

       

       boolean a;

       int s;

       System.out.println("Enter an int");

       s = myScanner.nextInt();

       a = hasEight(s);

       System.out.println(a);

       

   }

   private static boolean hasEight(int s)

   {

       String str = String.valueOf(s);

       return str.contains("8");

   }

   

}

7 0
3 years ago
Something is wrong with the logic in the program above. For which values of time will the greeting "Good Morning!" be displayed?
Klio2033 [76]

Answer:

There is logic problem in condition of elseif statement that is (time<20).

Explanation:

elseif(time<20) will be true for time<10 that means program will never greet good morning as to make logic correct either change condition from <em>elseif(time<20)</em> to <em>elseif(time<20&& time>=10)</em>. Or change the order of condition like check first for <em>elseif(time<10) </em>

solution 1

if (time < 6) { greeting = "It is too early!"; }

else if (time < 20 && time>=10) { greeting = "Good Day!"; }

else if (time < 10) { greeting = "Good Morning!"; }

else { greeting = "Good Evening!"; }

console.log(greeting);

solution 2

if (time < 6) { greeting = "It is too early!"; }

else if (time < 10) { greeting = "Good Morning!"; }

else if (time < 20 ) { greeting = "Good Day!"; }

else { greeting = "Good Evening!"; }

console.log(greeting);

7 0
3 years ago
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