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noname [10]
3 years ago
8

A7DF is the hexadecimal representation for what bit pattern?

Computers and Technology
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

1010 0111 1101 1111

Explanation:

A = 10 in decimal = 1010 in binary

7 = 7 in decimal = 0111 in binary

D = 13 in decimal = 1101 in binary

F = 15 in decimal = 1111 in binary

Therefore 0xA7DF = 1010 0111 1101 1111 in binary

You might be interested in
What field in a TCP segment is used to determine if an arriving data unit exactly matches the data unit sent by the source?]
MrRa [10]

Answer:

The correct answer to the following question will be "Checksum".

Explanation:

A variable that reflects the amount of several bits in a transmitted packet and is used by practitioners of IT to spot heavy-level anomalies in the transmission of data, known as Checksum.

  • After executing a cryptographic hashing algorithm each piece of information or a document could be allocated a value of checksum before delivery.
  • We are relevant because we are using them to verify the authenticity of the documents.

So, it's the right answer.

3 0
3 years ago
Help!! Best answer will get Brainliest!!
Eddi Din [679]

Answer:

answer(s):

-set goals

-select a topic

-write down research questions

Hope this helped and sorry for the bold. <3

Explanation:

6 0
2 years ago
Read 2 more answers
Write a class called Course that represents a course taken at a school. Represent each student using the modified Student class
Vinvika [58]

Answer:

The code is given below with its appropriate output

Explanation:

//Student.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Student {

public String firstName;

public String lastName;

public float[] marks;

Scanner scanner = new Scanner(System.in);

public Student(String firstName, String lastName) {

this.firstName = firstName;

this.lastName = lastName;

}

public void getdetail() {

System.out.println("enter only five marks");

marks = new float[5];

int count = 0;

for (int i = 0; i < 5; i++) {

float mark = 0;

++count;

if (count <= 5) {

System.out.println("enter score " + count);

mark = scanner.nextFloat();

if (mark >= 0.0 && mark <= 100.0)

marks[i] = mark;

else {

System.out.println("you entered mark is invalid");

marks[i] = 0;

}

} else

System.out.println(" maximum is five only");

}

}

public void tostring() {

System.out.println("firstname :" + "\t" + firstName + "\t" + "lastname :"

+ "\t" + lastName + "\n" + "the marks are");

int count = 0;

for (float mark : marks) {

count++;

System.out.println("the mark of " + count + " is " + mark);

}

}

public void Averagecal() {

float sum = 0.0f;

for (float mark : marks) {

sum = sum + mark;

}

float avg = sum / 5;

System.out.println("average of a student is " + avg);

}

}

//Course.java

import java.io.*;

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Course {

public String courseName;

public int number;

Student[] students;

Scanner scanner = new Scanner(System.in);

public Course(String courseName) {

this.courseName = courseName;

}

public void addStudents() {

System.out

.println("how many no of students you want to add for this particular course");

int count = scanner.nextInt();

students = new Student[count];

for (int i = 0; i < count; i++) {

System.out.println("enter the first name");

String fname = scanner.next();

System.out.println("enter the last name");

String lname = scanner.next();

Student s = new Student(fname, lname);

s.getdetail();

s.tostring();

s.Averagecal();

students[i] = s;

}

}

public void roll() {

int count = 0;

for (Student stud : students) {

count++;

}

System.out.println("the no of students in this " + courseName

+ " course is " + count);

}

}

//Driver.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Driver {

public static void main(String[] args) {

Course course = new Course("java");

course.addStudents();

course.roll();

}

}

<u>output: </u>

C:\Users\Daniel\Desktop\New folder>javac Student.java

C:\Users\Danie;\Desktop\New folder>javac Course.java

C:\Users\Daniel\Desktop\New folder>javac Driver.java

C:\Users\Daniel\Desktop\New folder>java Driver

how many no of students you want to add for this particular course ?

1

enter the first name

john

enter the last name

rich

enter only five marks

enter score 1

89

enter score 2

91

enter score 3

85

enter score 4

78

enter score 5

96

firstname : john lastname : rich

the marks are

the mark of 1 is 89.0

the mark of 2 is 91.0

the mark of 3 is 85.0

the mark of 4 is 78.0

the mark of 5 is 96.0

average of a student is 87.8

the no of students in this java course is 1

C:\Users\Ravi\Desktop\New folder>

3 0
3 years ago
You are able to drag a cell to a new location by pointing to the cell border until the pointer displays a _______ arrow, and the
ivann1987 [24]
I think its D, double-headed if I remember right. If this is brainiest can you mark it, please! I am trying to rank up. Thanks, hun!
7 0
3 years ago
Read 2 more answers
How many bits must be "flipped" (i.e., changed from 0 to 1 or from 1 to 0) in order to capitalize a lowercase that’s represented
Alexxandr [17]
Only one ... the third bit of the byte, numerical 32.  Every lower-case letter 
has a '1' in that place.  If that bit is changed to '0', then the code represents
the upper-case form of the same letter.
8 0
3 years ago
Read 2 more answers
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