If you use the X symbol on you calculator, the one and only accurate answer would be 4 in this situation, you could just say 2 plus 2 and you get the same answer!
hope this helped you in the future! ;)
Answer:
The 2 digit number is 36
Step-by-step explanation:
Let the 2 digits be x and y, then:
x + y = 9
10y + x = 27 + 10x + y
From the second equation:
-9x + 9y = 27 Divide through by 9:
-x + y = 3 Add this to th first equation:
2y = 12
y = 6.
and x= 9- 6 = 3.
Answer:
C. 16
Step-by-step explanation:
√16= 4 =2*2
pls mark me brainliest
![\purple{\twoheadrightarrow\bf 2cos^2A = 1 + cos2A }](https://tex.z-dn.net/?f=%5Cpurple%7B%5Ctwoheadrightarrow%5Cbf%20%202cos%5E2A%20%3D%201%20%2B%20cos2A%20%7D)
![\purple{\twoheadrightarrow\bf a^3 +b^3 = (a+b)^3 -3ab(a+b)}](https://tex.z-dn.net/?f=%5Cpurple%7B%5Ctwoheadrightarrow%5Cbf%20%20a%5E3%20%2Bb%5E3%20%3D%20%28a%2Bb%29%5E3%20-3ab%28a%2Bb%29%7D)
![\purple{\twoheadrightarrow\bf 2 sinA cosA = sin2A}](https://tex.z-dn.net/?f=%5Cpurple%7B%5Ctwoheadrightarrow%5Cbf%20%202%20sinA%20cosA%20%3D%20sin2A%7D)
________________________________________
1)
![\twoheadrightarrow\bf L.H.S](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%20L.H.S)
![\pink{\twoheadrightarrow\bf cos^4 x}](https://tex.z-dn.net/?f=%5Cpink%7B%5Ctwoheadrightarrow%5Cbf%20cos%5E4%20x%7D)
![\twoheadrightarrow\sf \dfrac{1}{4} (2cos^2x)^2](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%20%5Cdfrac%7B1%7D%7B4%7D%20%282cos%5E2x%29%5E2)
![\twoheadrightarrow\sf \dfrac{1}{4}(1+cos2x)^2](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%20%5Cdfrac%7B1%7D%7B4%7D%281%2Bcos2x%29%5E2)
![\twoheadrightarrow\sf \dfrac{1}{4}(1+2cos2x+cos^22x)](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%20%5Cdfrac%7B1%7D%7B4%7D%281%2B2cos2x%2Bcos%5E22x%29)
![\twoheadrightarrow\sf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times 2cos^22x](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%20%5Cdfrac%7B1%7D%7B4%7D%2B%5Cdfrac%7B1%7D%7B2%7Dcos2x%2B%5Cdfrac%7B1%7D%7B8%7D%5Ctimes%202cos%5E22x)
![\twoheadrightarrow\sf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times(1+cos4x)](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%20%5Cdfrac%7B1%7D%7B4%7D%2B%5Cdfrac%7B1%7D%7B2%7Dcos2x%2B%5Cdfrac%7B1%7D%7B8%7D%5Ctimes%281%2Bcos4x%29)
![\pink{\twoheadrightarrow\bf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times cos4x}](https://tex.z-dn.net/?f=%5Cpink%7B%5Ctwoheadrightarrow%5Cbf%20%5Cdfrac%7B1%7D%7B4%7D%2B%5Cdfrac%7B1%7D%7B2%7Dcos2x%2B%5Cdfrac%7B1%7D%7B8%7D%5Ctimes%20cos4x%7D%20)
![\twoheadrightarrow\bf R.H.S](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%20R.H.S)
______________________________________
2)
![\twoheadrightarrow\bf L.H.S](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%20L.H.S)
![\pink{\twoheadrightarrow\bf cos^6\theta +sin^6\theta }](https://tex.z-dn.net/?f=%5Cpink%7B%5Ctwoheadrightarrow%5Cbf%20cos%5E6%5Ctheta%20%2Bsin%5E6%5Ctheta%20%7D)
![\twoheadrightarrow\sf (cos^2\theta)^3 +(sin^2\theta)^3](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%20%28cos%5E2%5Ctheta%29%5E3%20%2B%28sin%5E2%5Ctheta%29%5E3)
![\twoheadrightarrow\sf (cos^2\theta +sin^2\theta)^3 -3cos^2\theta sin^2\theta (cos^2\theta +sin^2\theta)](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%20%28cos%5E2%5Ctheta%20%2Bsin%5E2%5Ctheta%29%5E3%20-3cos%5E2%5Ctheta%20sin%5E2%5Ctheta%20%28cos%5E2%5Ctheta%20%2Bsin%5E2%5Ctheta%29)
![\twoheadrightarrow\sf 1-3\times \dfrac{1}{4}\times 4(sin\theta cos\theta) ^2](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%201-3%5Ctimes%20%5Cdfrac%7B1%7D%7B4%7D%5Ctimes%204%28sin%5Ctheta%20cos%5Ctheta%29%20%5E2)
![\twoheadrightarrow\sf 1-\dfrac{3}{4}(2sin\theta cos\theta) ^2](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Csf%201-%5Cdfrac%7B3%7D%7B4%7D%282sin%5Ctheta%20cos%5Ctheta%29%20%5E2)
![\pink{\twoheadrightarrow\sf 1-\dfrac{3}{4}sin^22\theta}](https://tex.z-dn.net/?f=%5Cpink%7B%5Ctwoheadrightarrow%5Csf%201-%5Cdfrac%7B3%7D%7B4%7Dsin%5E22%5Ctheta%7D)
![\twoheadrightarrow\bf R.H.S](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%20R.H.S)