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dem82 [27]
2 years ago
5

Find the value of the expression below if I = 10. z? – 2 (x + 5) =

Mathematics
1 answer:
12345 [234]2 years ago
3 0

Answer:

10

Step-by-step explanation:

z−2(x+5)=

Use the distributive property to multiply −2 by x+5.

z−2x−10

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Black_prince [1.1K]

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$870

8.7×10²

Step-by-step explanation:

0.3×($900+$2,000)

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=$870

4 0
2 years ago
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Juliette [100K]

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Step-by-step explanation:

9+9+9=27

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8 0
3 years ago
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Data from an independent research company found that the annual cost per worker for insurance​ (health, life,​ liability, etc.)
lesantik [10]

Answer:

The cost per worker goes in five years from $67.81 at 1997, to $394.14 in 2001. It is an increase of $326.33 (481%).

f(0)=67.81e^{0.44\cdot 0}=67.81*1=67.81\\\\f(1)=67.81e^{0.44\cdot1}=67.81*1.553=105.29\\\\f(2)=67.81e^{0.44\cdot2}=67.81*2.411=163.48\\\\f(3)=67.81e^{0.44\cdot3}=67.81*3.743=253.84\\\\f(4)=67.81e^{0.44\cdot4}=67.81*5.812=394.14\\\\

Step-by-step explanation:

The annual cost per worker is modeled by the function:

f(x)=67.81e^{0.44\cdot x}

where x = years from 1997.

We have to calculate the cost per worker from 1997 to 2001, according to the function f(x).

We have:

f(0)=67.81e^{0.44\cdot 0}=67.81*1=67.81\\\\f(1)=67.81e^{0.44\cdot1}=67.81*1.553=105.29\\\\f(2)=67.81e^{0.44\cdot2}=67.81*2.411=163.48\\\\f(3)=67.81e^{0.44\cdot3}=67.81*3.743=253.84\\\\f(4)=67.81e^{0.44\cdot4}=67.81*5.812=394.14\\\\

The cost per worker goes in five years from $67.81 at 1997, to $394.14 in 2001. It is an increase of $326.33 (481%).

5 0
2 years ago
PT = 7x + 8 and TQ = 9x - 6
erastova [34]

Answer:

t is 7

Step-by-step explanation:

i did it

4 0
2 years ago
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